Answer:
a) 90.695 lb
b) 85.305 lb
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
(a) The 65th percentile
X when Z has a pvalue of 0.65. So X when Z = 0.385.
(b) The 35th percentile
X when Z has a pvalue of 0.35. So X when Z = -0.385.
Answer: 0.46, 0.056, the distribution is approximately normal
Step-by-step explanation: The shape is approximately normal since the expected number of successes equals 36.8 and the expected number of failures equals 43.2 are both larger than 10
The answer is 224.7 you got to turn 30% into decimal which is 0.30
then multiply 0.30 and 749 which equals 224.7
(4 – 2i)(6 + 2i)
FOIL
First : 4*6 =24
Outer: 4*2i = 8i
Inner: -2i* 6 = -12i
Last: -2i*2i = -4i^2 =-4(-1) =4
Add together
24+8i-12i+4
28-4i
Answer: 28-4i
Answer:
amount of pepper required= 7.5 tsp
amount of garlic powder required = 30 tsp
Step-by-step explanation:
Given,
amount of salt used for small batch of the recipe = 2 tsp
amount of pepper used for small batch of the recipe = 1 tsp
amount of garlic powder used for small batch of the recipe = 4 tsp
amount of salt used for the larger batch = 15 tsp
= 2 x 7.5 tsp
= amount of salt used for small batch the recipe x 7.5
So,
the amount of pepper needed for the larger batch= 7.5 x amount of pepper used for the small batch of recipe
= 7.5 x 1 tsp
= 7.5 tsp
the amount of garlic powder needed for the larger batch= 7.5 x amount of garlic powder used for the small batch of recipe
= 7.5 x 4 tsp
= 30 tsp
