-10w - 400 = o
w= weeks
o = new outstanding balance
(a) The probability that there is no open route from A to B is (0.2)^3 = 0.008.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:

(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:

β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:

Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:


Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.
Answer:
The p-value should be higher than 0.05
Step-by-step explanation:
solution is found below
Answer: 
Therefore, the algebraic exp
Step-by-step explanation:
Given : x represents the number of pounds of coffee A.
The total weight of the mix of coffee A and coffee B = 100 pounds.
Then , we have the following expression to represents the number of pounds of coffee B:-

Therefore, the algebraic expression that represents the number of pounds of coffee B. :-

If one labour works 200 hours per month, the amount of hot water heaters the labour can produce is = 200 × 0.25 = 50 hot water heaters
The demand is to produce 57600 hot water heaters
The number of labourers employed is 57600 ÷ 50 = 1152 labourers