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1 year ago

I WILL AWARD BRAINLIEST!! PLEASE HELP!!

Mathematics

1 answer:

MrRa [10]1 year ago

6 0

Answer:

1) By SAS theorem, ΔADE≅ΔCDF

2) By SSS theorem, ΔBDE≅ΔBDF

Step-by-step explanation:

Consider isosceles triangle ABC (see diagram).

1. In triangles ADE and CDF:

AD≅DC (since BD is median, then it divides side AC in two congruent parts);

AE≅CF (given);

∠A≅∠C (triangle ABC is isosceles, then angles adjacent to the base are congruent).

By SAS theorem, ΔADE≅ΔCDF.

2. In triangles BDE and BDF:

side BD is common;

DE≅DF (ΔADE≅ΔCDF, then congruent triangles have congruent corresponding sides);

BE≅FB (triangle ABC is isosceles, AB≅BC, AE≅CF, then BE=AB-AE, FB=BC-CF).

Be SSS theorem, ΔBDE≅ΔBDF.

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If f Superscript negative 1 Baseline (x) = negative one-fifth x, what is f Superscript negative 1 Baseline (x) = one-fifth x?

Artyom0805 [142]

Answer:

a different inverse function

Step-by-step explanation:

If $f^{-1}(x)=-\frac{1}{5}x$ then $f^{-1}(x)=\frac{1}{5}x$ is a different inverse function.

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5 0

1 year ago

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Data sets A and B are dependent. Find sd.Assume that the paired data came from a population that is normally distributed.A. 1.73

marusya05 [52]

Complete question :

A : 2.7, 3.7, 5.6, 2.6, 2.7

B : 5.1, 4.0, 3.9, 3.8, 5.2

Data sets A and B are dependent. Find sd.Assume that the paired data came from a population that is normally distributed.A. 1.73B. 1.21C. 1.32D. 1.89

Answer: A.1.73

Step-by-step explanation:

Given the data:

A : 2.7, 3.7, 5.6, 2.6, 2.7

B : 5.1, 4.0, 3.9, 3.8, 5.2

Difference betweenA and B (A - B) :

Xd = (A - B) = - 2.4, -0.3, 1.7, - 1.2, - 2.5

Sum of (A - B) = Σ Xd = (-2.4 + (-0.3) + 1.7 + (-1.2) + (-2.5) = - 4. 7

Md = ΣXd / n = - 4.7 / 5 = - 0.94

Xd - Md = (-2.4 + 0.94), (-0.3 + 0.94), (1.7 + 0.94), (-1.2 + 0.94), (-2.5 + 0.94)

(Xd - Md) = - 1.46, 0.64, 2.64, - 0.26, - 1.56

(Xd - Md)^2 = (-1.46)^2 + 0.64^2 + 2.64^2 + (-0.26)^2 + (-1.56)^2

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Standard deviation= √12.012 / 4

Standard deviation = 1.7329

Standard deviation= 1.73

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2 years ago

Automobile mechanics conduct diagnostic tests on 150 new cars of a particular make and model to determine the extent to which th

Aleks04 [339]

Answer:

99% Confidence interval: (0.185,0.375)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 150

Number of cars that have faulty catalytic converters, x = 42

$\hat{p} = \dfrac{x}{n} = \dfrac{42}{150} = 0.28$

99% Confidence interval:

$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

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Putting the values, we get:

$0.28\pm 2.58(\sqrt{\frac{0.28(1-0.28)}{150}}) = 0.28\pm 0.095\\\\=(0.185,0.375)$

The 99% confidence interval for the true proportion of new cars with faulty catalytic converters is (0.185,0.375)

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1 year ago

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elena-14-01-66 [18.8K]

<em><u>Your answer: </u></em> a reflection across the y-axis followed by a clockwise rotation 90° about the origin. A clockwise rotation 90° about the origin followed by a reflection across the x-axis. A counter-clockwise rotation 90° about the origin followed by a reflection across the y-axis. A reflection across the x-axis followed by a counter-clockwise rotation 90° about the origin.

Hope this helps <3

Stay safe

Stay Warm

-Carrie

Ps. It would mean a lot if you marked this brainliest

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1 year ago

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andriy [413]

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2 years ago

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