First, she needs to find her resting heart rate by counting her pulse for one minute immediately after she wakes up for 5 days i
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Answer:
So on this case the 95% confidence interval would be given by (11.393;15.857)
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Data: 14, 10, 13, 16, 12, 18, 15, 11
We can calculate the sample mean and deviation with the following formulas:
represent the sample mean
population mean (variable of interest)
s=2.669 represent the sample standard deviation
n=8 represent the sample size
Calculate the confidence interval
The confidence interval for the mean is given by the following formula:
(1)
In order to calculate the critical value we need to find first the degrees of freedom, given by:
Since the confidence is 0.95 or 95%, the value of and
, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,7)".And we see that
Now we have everything in order to replace into formula (1):
So on this case the 95% confidence interval would be given by (11.393;15.857)
Answer:
There is no significant difference between the two averages at 5% level
Step-by-step explanation:
Given that a a college student is interested in testing whether business majors or liberal arts majors are better at trivia.
The student gives a trivia quiz to a random sample of 30 business school majors and finds the sample’s average test score is 86. He gives the same quiz to 30 randomly selected liberal arts majors and finds the sample’s average quiz score is 89
Thus he has done a hypothesis testing for comparison of two means of different subjects. n =30
Since which is better is not claimed we use two tailed test here
We find that p value our alpha
Since p >alpha, we find that there is no significant difference between the averages of these two groups and null hypothesis is accepted