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Evgesh-ka [11]
2 years ago
11

First, she needs to find her resting heart rate by counting her pulse for one minute immediately after she wakes up for 5 days i

n a row. She finds her average resting heart rate to be 62 after
5 days and she remembers the last day's pulse was 58 and all the others were the same. Write and solve an equation to find what her pulse was on all the other days. Justify your answer by showing your steps. Put in Simple equation
Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
4 0

Answer:

63

Step-by-step explanation:

She finds her average resting heart rate to be 62 after  5 days.

That means, average of the 5 heart rate pulse=62

If the last day was 58 and all the other days were the same.

Let x be her pulse on the other days,

Then,

Average, 62=\dfrac{58+4x}{5}\\\text{Cross Multiply}\\58+4x=62 X 5\\\text{Suntract 58 from both sides}\\4x=(62X5)-58\\4x=310-58\\4x=252\\\text{Divide both sides by 4}\\x=63

Her pulse on all the other days is 63.

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Answer this please and thank you<br><br> If DE=4x-1, EF=9, and DF=9x-22, find the value of x.
dexar [7]

Question

If DE = 4x-1, EF = 9, and DF = 9x-22, find the value of x.

Answer

x = 6

8 0
2 years ago
23% of U.S adults say they are more likely to make purchases during a sales tax holiday. You randomly select 10 adults. Find the
algol13

Answer:

a) 0.294

b) 0.414

c) 0.694

Step-by-step explanation:

Use binomial probability.

P = nCr pʳ qⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

In this case, n = 10, p = 0.23, and q = 0.77.

a) If r = 2, then the probability is:

P = ₁₀C₂ (0.23)² (0.77)¹⁰⁻²

P = 45 (0.23)² (0.77)⁸

P = 0.294

b) If r > 2, then the probability is 1 − P(r ≤ 2).

P = 1 − ₁₀C₀ (0.23)⁰ (0.77)¹⁰⁻⁰ − ₁₀C₁ (0.23)¹ (0.77)¹⁰⁻¹ − ₁₀C₂ (0.23)² (0.77)¹⁰⁻²

P = 1 − 1 (0.23)⁰ (0.77)¹⁰ − 10 (0.23)¹ (0.77)⁹ − 45 (0.23)² (0.77)⁸

P = 1 − 0.073 − 0.219 − 0.294

P = 0.414

c) If 2 ≤ r ≤ 5, then the probability is:

P = ₁₀C₂ (0.23)² (0.77)¹⁰⁻² + ₁₀C₃ (0.23)³ (0.77)¹⁰⁻³ + ₁₀C₄ (0.23)⁴ (0.77)¹⁰⁻⁴ + ₁₀C₅ (0.23)⁵ (0.77)¹⁰⁻⁵

P = 45 (0.23)² (0.77)⁸ + 120 (0.23)³ (0.77)⁷ + 210 (0.23)⁴ (0.77)⁶ + 252 (0.23)⁵ (0.77)⁵

P = 0.294 + 0.234 + 0.122 + 0.044

P = 0.694

8 0
2 years ago
The time it takes to transmit a file always depends on the file size. Suppose you transmitted 30 files, with the average size of
Ostrovityanka [42]

Answer:

Y = 0.009042 + 0.0002457X

Y = 0.1073 seconds

Step-by-step explanation:

In the given problem we have two variables: the transmission time and average size of file.

Y = transmission time

X = average file size

The linear regression model is given by

Y = a + bX

The slope b is given by

b = correlation coefficient*(SDy/SDx)

Where SDy is the standard deviation of average transmittance time and SDx is the standard deviation of average file size.

b = 0.86(0.01/35)

b = 0.0002457

The y-intercept a is given by

a = y - bx

a =  0.04 - (0.0002457)126

a = 0.04 - 0.030958

a = 0.009042

Therefore, the linear regression model is

Y = 0.009042 + 0.0002457X

Predict the time it will take to transmit a 400 Kbyte file.

Substitute X = 400 in the regression model

Y = 0.009042 + 0.0002457(400)

Y = 0.009042 + 0.09828

Y = 0.1073 seconds

Therefore, the predicted time to transmit a 400 Kbyte file is 0.1073 seconds.

8 0
2 years ago
a sports statistician claim that the mean winning times for boston marathon women's open division champions is at least 2.68 hou
GenaCL600 [577]

Answer:

We conclude that the mean winning times for Boston marathon women's open division champions is at least 2.68 hours.

Step-by-step explanation:

We are given that a sports statistician claim that the mean winning times for Boston marathon women's open division champions is at least 2.68 hours.

The mean winning time of a sample of 30 randomly selected Boston marathon women's open division champions is 2.60 hours. assume the population standard deviation is 0.32 hours.

<em>Let </em>\mu<em> = </em><u><em>mean winning times for Boston marathon women's open division champions.</em></u>

So, Null Hypothesis, H_0 : \mu\geq 2.68 hours      {means that the mean winning times for Boston marathon women's open division champions is at least 2.68 hours}

Alternate Hypothesis, H_A : p < 2.68 hours      {means that the mean winning times for Boston marathon women's open division champions is less than 2.68 hours}

The test statistics that would be used here <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                        T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean winning time = 2.60 hours

            \sigma = population standard deviation = 0.32 hours

            n = sample of women's open division champions = 30

So, <em><u>test statistics</u></em>  =   \frac{2.60-2.68}{\frac{0.32}{\sqrt{30} } }

                               =  -1.37

The value of z test statistics is -1.37.

Now, P-value of the test statistics is given by following formula;

         P-value = P(Z < -1.37) = 1 - P(Z \leq 1.37)

                       = 1 - 0.9147 = <u>0.0853</u>

Since, P-value of the test statistics is more than the level of significance as 0.0853 > 0.05, so <u>we have insufficient evidence to reject our null hypothesis</u> as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean winning times for Boston marathon women's open division champions is at least 2.68 hours.

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2 years ago
What is it called when you put two of the same variables together
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Answer:

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2 years ago
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