The formula for the remaining volume of fuel in a car's tank is I-E\cdot DI−E⋅DI, minus, E, dot, D, where III is the initial vol
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Answer:
1.75 cm
Step-by-step explanation:
We are given that the dimensions of the box as 25 cm by 14 cm by 10 cm.
Now, to increase the profit, the dimensions of the box by 'x' cm.
Thus, the new dimensions are (25-x) cm by (14-x) cm by (10-x) cm.
Further, it is given that the volume of the new box is 2,208
As, Volume of the box = Length × Breadth × Height
i.e. 2208 = (25-x) × (14-x) × (10-x)
i.e.
i.e.
i.e.
On solving this cubic equations, we get that, the solutions are x = 27.6, x = 1.75 and x = 26.8.
Since, the dimensions 25 cm by 14 cm by 10 cm are reduced by x cm.
Thus, if x = 27.6 or x = 26.8, then (10-x) = -17.6 or -16.8, which cannot be possible. So, x = 1.75 cm.
Hence, the dimensions were decreased by 1.75 cm.