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jonny [76]
2 years ago
5

Meg has a can that contains 80% orange juice and the rest water. The can has 1 liter of water. Part A: Write an equation using o

ne variable that can be used to find the total number of liters of orange juice and water in the can. Define the variable used in the equation.
Mathematics
1 answer:
Marysya12 [62]2 years ago
8 0

<u>Answer</u>

Part 1:  

Total number of liters of orange juice = 0.8x

Total number of liters of water = 0.2x

Part 2: The variable x represent the amount of full capacity of the container.


<u>Explanation</u>

Let x be the volume of the container.

Total number of orange juice = 80% of x

                                                 = 80/100 × x

                                                  = 0.8 × x

                                                 = 0.8x liters

If 80% of the container has orange juice the water will be =(100 - 80)%

                                                                                                 = 20%

The total number of liters of water = 20% of x

                                                           = 20/100 × x

                                                            = 0.2 × x

                                                           = 0.2x liters.

X ⇒The variable represent the total volume of the container. That is the full capacity of the container.

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Javier is comparing costs of two cars. Car A costs $130 per month for insurance and $0.10 per mile to run. Car B costs $108 per
kvv77 [185]

Answer:

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1 year ago
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The organizers of a talent show have budgeted $1800 to buy souvenir clothing to sell at the event. They can buy shirts for $10 e
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Let s represent number of shirts and h represent number of hats.

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Subtract 12h+1 from 34h+4 . what is the answer? a.−1/4h+5 b.1/4h+5 c.−1/4h d.1/4h+3
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2 years ago
The frequency distribution of weights (in kg) of 40 persons is given below.
gregori [183]

Answer: (a) 4

(b) 5

(c) 14

(d)

Class interval       Class mark

30 - 35                       \dfrac{35+30}{2}=32.5

35 - 40                       \dfrac{35+40}{2}=37.5

40 - 45                        \dfrac{40+45}{2}=42.5

45 - 50                        \dfrac{45+50}{2}=47.5

50 - 55                        \dfrac{50+55}{2}=52.5

Step-by-step explanation:

The data of 40 persons is given as :

Weights (in kg)    Frequency

30 - 35                  6

35 - 40                   13

40 - 45                   14

45 - 50                   4

50 - 55                  3

(a)

<em>Lower limit is the lowest number in a class interval .</em>

So, is the lower limit of fourth-class interval (45 - 50) is 4.

(b)

<em>Class size = Upper limit - lower limit </em>

So, Class size of first class interval = 35-30=5

Thus , class size of each interval is 5. [ class size remains same]

(c)

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Thus , 40 - 45  is the class interval has the highest frequency.

(d)

<em>Class mark is the mid value of each class interval.</em>

<em>Class interval = </em>\dfrac{(\text{Upper limit+Lower limit})}{2}

Class interval       Class mark

30 - 35                       \dfrac{35+30}{2}=32.5

35 - 40                       \dfrac{35+40}{2}=37.5

40 - 45                        \dfrac{40+45}{2}=42.5

45 - 50                        \dfrac{45+50}{2}=47.5

50 - 55                        \dfrac{50+55}{2}=52.5

8 0
1 year ago
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