a) If side a measures 90 feet and side b measures 120 feet, how many feet of flowers will be planted along side c, the hypotenus
1 answer:
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Let's call the lengths of our two types of sides <em />
and 
.
The two sides will that our 1.3 inches bigger than the third side will be have length x, and the length of the other side will be known as y. Thus,
.
Considering this, we can add our sides together and set this value equal to 8, given the information in the problem:
Now, let's solve for y.
Now, we are not done yet. We must determine the true lengths of all of our sides. Using the equation we found earlier, the length of the two bigger sides is
inches and the length of our smaller side is simply 
inches.
To verify, we can add these sides together and check that they equal 8:
3.1 + 3.1 + 1.8 = 8 ✔
The two sides will that our 1.3 inches bigger than the third side will be have length x, and the length of the other side will be known as y. Thus,
Considering this, we can add our sides together and set this value equal to 8, given the information in the problem:
Now, let's solve for y.
Now, we are not done yet. We must determine the true lengths of all of our sides. Using the equation we found earlier, the length of the two bigger sides is
To verify, we can add these sides together and check that they equal 8:
3.1 + 3.1 + 1.8 = 8 ✔
Answer:
MArginal productivity:
We can interpret this as he will reduce his time an <em>additional </em>0.0002 seconds for every <em>additional </em>yard he trains.
Step-by-step explanation:
The marginal productivy is the instant rate of change in the result for an increase in one unit of a factor.
In this case, the productivity is the time he last in the 100-yard. The factor is the amount of yards he train per week.
The marginal productivity can be expressed as:
where dt is the variation in time and dL is the variation in training yards.
We can not derive the function because it is not defined, but we can approximate with the last two points given:
Then we can interpret this as he will reduce his time an <em>additional </em>0.0002 seconds for every <em>additional </em>yard he trains.
This is an approximation that is valid in the interval of 60,000 to 70,000 yards of training.