Hi,
To find the number of small cylinders that fit inside the big cylinder. You need to divide volume of small cylinder with the volume of big cylinder. We do this by using formula to calculate volume of cylinder:
To find radius just divide diameter with 2.
Now just division:
Answer: You could fit 374.8 smaller cylinders inside a big cylinder.
Hope this helps.
r3t40
Given:
Total number of girls in her class = 16
Total number of boys in her class = 14
To find:
The number of different ways of choosing one girl and one boy.
Solution:
We have,
Total number of girls = 16
Total number of boys = 14
So,
Total number of ways to select one girl from 16 girls = 16
Total number of ways to select one boy from 14 boys = 14
Now, number of different ways of choosing one girl and one boy is
Therefore, the required number of different ways is 224.
Answer:
12 teachers will get 1/2 sheets each
Step-by-step explanation:
Noor bought 21 sheets of stickers
She gave 1/3 sheets to each 45 students
She wants to give teachers 1/2 of sheets
The question should be: how many teachers will she give
Total sheets=21
Students gets= 1/3 × 45
=45/3
=15 sheets
Remaining sheet= total sheets - students sheets
=21-15
=6 sheets
There are 6 sheets remaining for teachers
She wants to give 1/2 to each teacher
Then,
The number of teachers that will get =Remaining sheets ÷ each teacher's share
=6 ÷1/2
=6 × 2/1
=12 teachers
12 teachers will get 1/2 sheets each
2,070mg 86%
— = —
? mg 100%
Cross multiply (2,070 X 100) which equals 207,000
Then divide 207,000 by 86 which equals
2,406.976
Then you round so you get 2,407
The Answer is 2,407 milligrams
You're looking for the extreme values of 
subject to the constraint 
.
The target function has partial derivatives (set equal to 0)
so there is only one critical point at 
. But this point does not fall in the region . There are no extreme values in the region of interest, so we check the boundary.
Parameterize the boundary of by
with 
. Then 
can be considered a function of 
alone:
has critical points where 
:
but 
for all , so this case yields nothing important.
At these critical points, we have temperatures of
so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.
