If

of students were juniors and seniors that leaves the 36 sophomores to be

or

of attendees. I got

by converting

and adding it to

.
Now if 36 is

of the equation that means theirs at least 36 juniors and seniors.
Lets start with seniors. there should be just over 36 of them there. Lets start by multiplying 36 by

to figure out how many

is.
The equation would look like this 36*(3/12)
start with 3/12. this equals .25 or

.
Now multiply 36 by .25. this equals 9.
We have 9 students per

of the attendees.
To get the amount of seniors add 9 to 36

because we already stated

is 36.
36+9=45
Now to find the juniors add another 9 to create

.
45+9=54
In total you have:
36 sophomores
54 juniors
45 seniors<span />
Answer:
the answer is contained in the attachment
Step-by-step explanation:
for complete explanation kindly check the attachment.
Answer:
t = 460.52 min
Step-by-step explanation:
Here is the complete question
Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.
Solution
Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.
inflow = 0 (since the incoming water contains no dye)
outflow = concentration × rate of water inflow
Concentration = Quantity/volume = Q/200
outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.
So, Q' = inflow - outflow = 0 - Q/100
Q' = -Q/100 This is our differential equation. We solve it as follows
Q'/Q = -1/100
∫Q'/Q = ∫-1/100
㏑Q = -t/100 + c

when t = 0, Q = 200 L × 1 g/L = 200 g

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

㏑0.01 = -t/100
t = -100㏑0.01
t = 460.52 min
Answer:
y = 7,595.96(1.02)x
Step-by-step explanation:
y = 7,595.96(1.02)x
a normal linear equation is basically y = x + b
in this case,
- y = amount of money in the bank account
- x = number of years
- b is not required because there are no new deposits or withdrawals from the account
Since the accounts earns 2% interest per year, then you need to multiply the original amount by 1.02. As more years pass, the account will increase by 1.02, so the account increases by 1.02x. Since the original amount is $7,595.96, that will be our starting point.