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ANEK [815]
1 year ago
9

Solve 4/x-4=x/x-4-4/3 for x and determine if the solution is extraneous or not

Mathematics
1 answer:
4vir4ik [10]1 year ago
7 0

<u>Answer:</u>

x = 4 (extraneous solution)

<u>Step-by-step explanation:</u>

\frac { 4 } { x - 4 } = \frac { x } { x - 4 } - \frac { 4 } { 3 } \\ \frac { 4 } { x - 4 } - \frac { x } { x - 4 } = - \frac { 4 } { 3 } \\ \frac { 4 - x } { x - 4 } = - \frac { 4 } { 3 } \\ 3 ( 4 - x ) = - 4 ( x - 4 ) \\ 1 2 - 3 x = - 4 x + 1 6 \\ 4 x - 3 x = 1 6 - 1 2 \\ x = 4 \\

This solution is extraneous. Reason being that even if it can be solved algebraically, it is still not a valid solution because if we substitute back x=4, we will get two fractions with zero denominator which would be undefined.

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On a coordinate plane, a triangle has points (negative 5, 1), (2, 1), (2, negative 1).
daser333 [38]

Answer:

Step-by-step explanation:

Given a triangle has points:

(-5,1),(2,1), (2,-1)

Let us label the points:

A(2,1),

B(-5,1) and  

C(2,-1)

To find:

Distance between (−5, 1) and (2, −1) i.e. BC.

Horizontal leg AB and

Vertical leg, AC.

Solution:

Please refer to the attached diagram for the labeling of the points on xy coordinate plane.

We can simply use Distance formula here, to find the distance between two coordinates.

Distance formula :

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

For BC:

x_2 = 2\\x_1 = -5\\y_2 = -1\\y_1 = 1

BC = \sqrt{(2--5)^2+(-1-1)^2} = \sqrt{63}

Horizontal leg, AC:

x_2 = -5\\x_1 = 2\\y_2 = 1\\y_1 = 1

AC = \sqrt{(2-(-5))^2+(1-1)^2} = 7

Vertical Leg,  AB:

x_2 = 2\\x_1 = 2\\y_2 = -1\\y_1 = 1

AB = \sqrt{(2-2)^2+(-1-1)^2} = 2

5 0
2 years ago
Read 2 more answers
Determine the input value for which the statement f(x) = g(x) is true. From the graph, the input value is approximately_______ .
Julli [10]

In this question , we have a graph given, and we have to find the x coordinate of the intersection point .

From the graph , the input value is approximately 3.3 .

In the graph,

f(x) =3

And for g(x), we need the slope and y intercept .

Slope is the ratio of rise and run .

Here rise equals 3 units and run equals 2 units. And the graph touch the y axis at -2 .

So the equation of g(x) is

g(x) = \frac{3}{2}x -2

We need to do

f(x)= g(x)

Substituting the values of the two functions, we will get

3 = \frac{3}{2}x -2

Adding 2 to both sides

5 = \frac{3}{2}x

Cross multiplication

10 =3x&#10;\\&#10;x = \frac{10}{3}

x = 3.3

So the input value is 3.3 approx


6 0
1 year ago
Read 2 more answers
Megan wants to build a fence around her pool. The pool is 28 feet long by 23 feet wide. The fence is to be 15 feet from the edge
ASHA 777 [7]
23 +30 (15 feet each way) = 53

28 + 30 = 58

58 x 53 = 3074ft
7 0
1 year ago
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Kenny types 280 words. How long did he <br> type for?<br> A.4<br> B. 5<br> C.6<br> D. 7
zlopas [31]
Are you sure you didn’t miss anything while writing the question?

Cause we have nothing to go off. Everybody types differently so there is no way for us to say how long he typed for, unless we were given aprox how many words he wrote in a minute or something
5 0
1 year ago
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Which expression can be used to find the price of a $400 telescope after a 32% markup? Select all that apply.
blagie [28]
<h3>Option D</h3><h3>The expression can be used to find the price of a $400 telescope after a 32% markup is: 400 + 400 (0.32 )</h3>

<em><u>Solution:</u></em>

Given that,

Price of telescope = $ 400

Mark up = 32 %

To find: Cost after mark up

The formula used is:

<h3>Cost after mark up = Price of telescope + 32 % of Price of telescope</h3>

Therefore,

Cost after mark up = 400 + 32 % of 400

\text{Cost after mark up } = 400 + \frac{32}{100} \times 400\\\\\text{Cost after mark up } = 400 + 0.32 \times 400\\\\\text{Cost after mark up } = 400 + 128\\\\\text{Cost after mark up } = 528

Thus cost after mark up is $ 528 and expression is 400 + 400 (0.32 )

7 0
2 years ago
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