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ANEK [815]
1 year ago
9

Solve 4/x-4=x/x-4-4/3 for x and determine if the solution is extraneous or not

Mathematics
1 answer:
4vir4ik [10]1 year ago
7 0

<u>Answer:</u>

x = 4 (extraneous solution)

<u>Step-by-step explanation:</u>

\frac { 4 } { x - 4 } = \frac { x } { x - 4 } - \frac { 4 } { 3 } \\ \frac { 4 } { x - 4 } - \frac { x } { x - 4 } = - \frac { 4 } { 3 } \\ \frac { 4 - x } { x - 4 } = - \frac { 4 } { 3 } \\ 3 ( 4 - x ) = - 4 ( x - 4 ) \\ 1 2 - 3 x = - 4 x + 1 6 \\ 4 x - 3 x = 1 6 - 1 2 \\ x = 4 \\

This solution is extraneous. Reason being that even if it can be solved algebraically, it is still not a valid solution because if we substitute back x=4, we will get two fractions with zero denominator which would be undefined.

You might be interested in
A lottery sells 1000 tickets at $1 apiece. There is one winner who receives $100, and 5 second place winners who receive $50 eac
DaniilM [7]
Chance of winning $100 = 1/1000 
<span>chance of winning $50 = 5/1000 = 1/200 </span>
<span>cost of ticket = -1 </span>
<span>E[x] = 100* 1/1000 + 50* 1/200 -1 </span>
<span>= 0.1 + 0.25 - 1 = -0.65 

Hope this helps</span>
5 0
1 year ago
Find a26 in the arithmetic sequence: -15, -35, -55, -75
MrRissso [65]

Answer: x=−5

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−4−7x=31

−4+−7x=31

−7x−4=31

Step 2: Add 4 to both sides.

−7x−4+4=31+4

−7x=35

Step 3: Divide both sides by -7.

−7x

−7

=

35

−7

x=−5

4 0
2 years ago
Suppose that a manager is interested in estimating the average amount of money customers spend in her store. After sampling 36 t
musickatia [10]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The 90% confidence interval for this case would be (38.01, 44.29) and is given.

The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .

And the best option would be:

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

Step-by-step explanation:

Assuming this complete question: Which statement gives a valid interpretation of the interval?

The store manager is 90% confident that the average amount spent by the 36 sampled customers is between S38.01 and $44.29.

There is a 90% chance that the mean amount spent by all customers is between S38.01 and $44.29.

There is a 90% chance that a randomly selected customer will spend between S38.01 and $44.29.

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The 90% confidence interval for this case would be (38.01, 44.29) and is given.

The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .

And the best option would be:

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

8 0
2 years ago
Travis is considering taking out a 20-year loan with monthly payments of
d1i1m1o1n [39]

Answer:

travis monthly payment $350 the amt of the loan that he is considering taking out would be less than $79,504.54

Step-by-step explanation:

Apex

8 0
2 years ago
Read 2 more answers
The following chart shows a store?s records of coat sales over two years. 2 circle graphs. A circle graph titled 2006. Top coats
Mkey [24]

Answer:

<u>The correct answer is A. 16.5%</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly and to calculate the trend:

                   2006      2007  Trend

Top Coats    297        223       -24.92%

Parkas          210        210         + 0%  

Jackets         213        285        +33.80%

Raincoats      137        259        +89.05

Trench coats 103       127         +23.30%

Total               960     1,104        +15%

2. If the trend shown in these graphs stays constant, what percent of the market will parkas occupy in 2008?

Let's calculate the percent of the market occupied by parkas.

In 2006 = 210/960 = 21.88%

In 2007 = 210/1,104 = 19.02%

In 2008 = 210/1,270 = 16.54% (210 + 0 = 210; 1,104 + 15% = 1,270)

<u>The correct answer is A. 16.5%</u>

7 0
2 years ago
Read 2 more answers
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