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KengaRu [80]
1 year ago
10

Morena is painting her bedroom and has a triangle of space left over as shown below. What is the area of the space Morena still

needs to paint?
(Showing image of a scalene triangle with 5 feet for the height and 26 feet for the base in total, and the non-painted section's base is shorter than the rest of the base)

A. 31 ft2 B. 65 ft2 C. 130 ft2 D. Not enough information
Mathematics
1 answer:
aleksandrvk [35]1 year ago
7 0

The answer is Letter c

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In an inventory of 100 sodas, 65 are
Ratling [72]

Answer:

5% I think

Step-by-step explanation:

Its mostly just a guess but I think its 5%

8 0
2 years ago
Your band is one of 8 bands competing at the battle of the bands. The order of the performances is determined at random. The fir
lorasvet [3.4K]

Answer:

1.79 %.

Step-by-step explanation:

you have to calculate the probability of a series of events before you can calculate the final probability.

The first event is that the band plays on Friday.

If there are 8 bands, but only 5 play on Friday, then the probability that they will play on Friday is

5/8

Now, the second event that they are the last ones is 1/5, since they are 5 bands.

Therefore the probability that they will play on Saturday and last is

5/8 * 1/5 = 1/8

Now, for the rival band it would be, knowing that on Friday there is already a quota assigned and one band less, the probability that they will play that day is

4/7

as they play before the other group, it would be 1/4, as there is already a quota assigned.

The final probability would then be:

4/7 * 1/4 = 1/7

Now the probability that the band gives the last performance on Friday night and your rival band performs immediately before them, is:

1/8 * 1/7 = 0.0179

That is 1.79 %.

3 0
2 years ago
What is the answer please
Marina86 [1]
Hey there!

Use The Pythagorean theorem. It’s a^2+b^2=c^2. Plug in 11 and 60. The equation would be 11^2+60^2=c^2. Simplify to get 121+3600=c^2. Simplify again to get 3721=c^2. Sqaure root each side to get c=61. The answer is the last one, c=61.

I hope this helps!
8 0
2 years ago
Customers are used to evaluate a preliminary product design. In the past, 95% of highly successful products received good review
Sever21 [200]

Answer:

a. 61.5%; b. About 61.8%; c. About 36.4%

Step-by-step explanation:

This is a kind of question that we can solve using the Bayes' Theorem. We have here all the different conditional probabilities we need to solve this problem.

According to that theorem, the probability of a selected product attains a good review is:

\\ P(G) = P(G|H)*P(H) + P(G|M)*P(M) + P(G|P)*P(P) (1)

In words, the probability that a selected product attains a <em>good review</em> is an <em>event </em>that depends upon the sum of the conditional probabilities that the product comes from <em>high successful product</em> P(G|H) by the probability that this product is a <em>highly successful product</em> P(H), plus the same about the rest of the probabilities, that is, P(G|M)*P(M) or the probability that the product has a good review coming from a <em>moderately successful</em> product by the probability of being moderately successful, and a good review coming from a poor successful product by the probability of being poor successful or P(G|P)*P(P).

<h3>The probability that a randomly selected product attains a good review</h3>

In this way, the probability that a randomly selected product attains a good review is the result of the formula (1). Where (from the question):

P(G|H) = 95% or 0.95 (probability of receiving a good review being a highly successful product)

P(G|M) = 60% or 0.60 (probability of receiving a good review being a moderately successful product)

P(G|P) = 10% or 0.10 (probability of receiving a good review being a poorly successful product)

P(H) = 40% or 0.40 (probability of  being a highly successful product).

P(M) = 35% or 0.35 (probability of  being a moderately successful product).

P(P) = 25% or 0.25 (probability of  being a poor successful product).

Then,

\\ P(G) = P(G|H)*P(H) + P(G|M)*P(M) + P(G|P)*P(P)

\\ P(G) = 0.95*0.40 + 0.60*0.35 + 0.10*0.25

\\ P(G) = 0.615\;or\; 61.5\%

That is, <em>the probability that a randomly selected product attains a good review</em> is 61.5%.

<h3>The probability that a new product attains a good review is a highly successful product</h3>

We are looking here for P(H|G). We can express this probability mathematically as follows (another conditional probability):

\\ P(H|G) = \frac{P(G|H)*P(H)}{P(G)}

We can notice that the probability represents a fraction from the probability P(G) already calculated. Then,

\\ P(H|G) = \frac{0.95*0.40}{0.615}

\\ P(H|G) =\frac{0.38}{0.615}

\\ P(H|G) =0.618

Then, the probability of a product that attains a good review is indeed a highly successful product is about 0.618 or 61.8%.

<h3>The probability that a product that <em>does not attain </em>a good review is a moderately successful product</h3>

The probability that a product does not attain a good review is given by a similar formula than (1). However, this probability is the complement of P(G). Mathematically:

\\ P(NG) = P(NG|H)*P(H) + P(NG|M)*P(M) + P(NG|P)*P(P)

P(NG|H) = 1 - P(G|H) = 1 - 0.95 = 0.05

P(NG|M) = 1 - P(G|M) = 1 - 0.60 = 0.40

P(NG|P) = 1 - P(G|M) = 1 - 0.10 = 0.90

So

\\ P(NG) = 0.05*0.40 + 0.40*0.35 + 0.90*0.25

\\ P(NG) = 0.385\;or\; 38.5\%

Which is equal to

P(NG) = 1 - P(G) = 1 - 0.615 = 0.385

Well, having all this information at hand:

\\ P(M|NG) = \frac{P(NG|M)*P(M)}{P(NG)}

\\ P(M|NG) = \frac{0.40*0.35}{0.385}

\\ P(M|NG) = \frac{0.14}{0.385}

\\ P(M|NG) = 0.363636... \approx 0.364

Then, the <em>probability that a new product does not attain a good review and it is a moderately successful product is about </em>0.364 or 36.4%.

8 0
2 years ago
Which is equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x?
sergeinik [125]

Solving  RootIndex 3 StartRoot 8 EndRoot Superscript x we get =2^x

Step-by-step explanation:

We need to find equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x

Writing in mathematical form:

(\sqrt[3]{8})^x

Solving:

We know 8= 2x2x2= 2^3

and \sqrt[3]{x}=x^{\frac{1}{3}}

Applying these rules:

=((2^3)^{\frac{1}{3}})^x

=(2^{\frac{3}{3}})^x\\

=2^x

So, solving  RootIndex 3 StartRoot 8 EndRoot Superscript x we get =2^x

Keywords: Radical Expression

Learn more about Radical Expression at:

  • brainly.com/question/7153188
  • brainly.com/question/10534381

#learnwithBrainly

8 0
2 years ago
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