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Harrizon [31]
1 year ago
14

Jason Witten's Salary Negotiation Let's say that tight end Jason Witten (a football player) was given two options when negotiati

ng his contract for the 2017 football season (which was his final season, ). Option 1 was that he would be paid an additional $0.01 (yes one red cent) if he makes only one catch for the season, $0.02 if he makes a total of two catches, $0.04 for a total of three catches and so on, doubling the amount with each catch. Option 2 was that he would be paid a flat $2,000,000 increase from the previous year. Basing this decision on the 2012 season (where he had a career high of 110 total receptions/catches), which option would increase his salary more? (In other words, is it better for him to be paid per catch, starting with 1 cent and doubling with each catch up to 110 or is it better to have a flat $2 million increase?)
Mathematics
1 answer:
Leokris [45]1 year ago
3 0

Answer:

Option 1: It is better for him to be paid per catch, starting with 1 cent and doubling with each catch up to 110

Explanation:

If Jason were to be paid per catch given that he makes a total of 110 catches for the 2017 season in his new contract, he would make a total of :

0.01 × 2^109 = $6.4903711e+30(calculator result, means 6 then 30 digits after)

Therefore it is better for Jason to be paid per catch and not a flat fee of $2000000

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this net will be folded to form a prism. which pairs of faces will be opposite one another when the prism is created? check all
lesya [120]

Answer:

  1. d and f   2.a and c  3.b and e

Step-by-step explanation:

6 0
1 year ago
A random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a st
Orlov [11]

Answer:

95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

Step-by-step explanation:

We are given that a random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a standard deviation of 2.3 credit hours.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                          P.Q. = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample credit hours per quarter = 15.2 credit hours

             s = sample standard deviation = 2.3 credit hours

             n = sample of students = 250

             \mu = population mean credit hours per quarter

<em>Here for constructing 95% confidence interval we have used One-sample t test statistics as we know don't about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.96 < t_2_4_9 < 1.96) = 0.95  {As the critical value of t at 249 degree of

                                        freedom are -1.96 & 1.96 with P = 2.5%}  

P(-1.96 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u><em>95% confidence interval for</em></u> \mu = [ \bar X-1.96 \times {\frac{s}{\sqrt{n} } } , \bar X+1.96 \times {\frac{s}{\sqrt{n} } } ]

                  = [ 15.2-1.96 \times {\frac{2.3}{\sqrt{250} } } , 15.2+1.96 \times {\frac{2.3}{\sqrt{250} } } ]

                  = [14.915 hours , 15.485 hours]

Therefore, 95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

<em>The interpretation of the above confidence interval is that we are 95% confident that the true mean credit hours taken by a student each quarter will be between 14.915 credit hours and 15.485 credit hours.</em>

8 0
1 year ago
A student spent 2 hours studying, 1 hour doing laundry, and 1 ½ hours watching television. What percentage of time was spent doi
ivanzaharov [21]
Total hours working = 4.5 hrs 
hours doing laundry = 1 hr 

Percentage of time doing laundry = 1/4.5 
Percentage of time doing laundry = 22.22%

5 0
2 years ago
Read 2 more answers
Simplify: –3(y + 2)2 – 5 + 6y What is the simplified product in standard form? y2 + y +
gayaneshka [121]
-3(y+2)2-5+6y
Steps
Multiply the numbers: 3 x 2 = 6
= -6(y + 2) - 5 + 6y
Then, expand - 6(y + 2): -6y - 12
= -6y - 12-5 + 6y
Simplify
-6y - 12 - 5 + 6y
= -17
3 0
2 years ago
Read 3 more answers
Given the function f(x) = −5x2 − x + 20, find f(3).
lana66690 [7]


f(x) = -5x^2 - x + 20;

f(3) = -5*3^2 - 3 + 20 = -5*9 - 3 + 20 = -45 - 3 + 20 = -28;

3 0
1 year ago
Read 2 more answers
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