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1 year ago

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Every 2 weeks , each mayhem motorsports employee is expected to sell 8 vehicles . If a mayhem motorspot employee works for 12 we

eks , how many vehicles will they be expected to sell?

1 answer:

Bas_tet [7]1 year ago

4 0

They will be expected to sell 48 vehicles

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How does the area of triangle RST compare to the area of triangle LMN? The area of △RST is 2 square units less than the area of

sashaice [31]

Inscribe triangle RST in the square with dimensions 4×4, as shown in the figure.

from the area of this square, 4*4=16, we remove the triangles with dimensions
3×4, 2×1 and 2×4, whose side lengths are shown in the figure, and we are left with the area of triangle RST.

so $Area(RTS)=16- \frac{1}{2}*3*4- \frac{1}{2}*2*1- \frac{1}{2}*2*4=16-6-1-4=5$ units squared

similarly,

$Area(LMN)=4*3- \frac{1}{2}*1*4- \frac{1}{2}*2*2- \frac{1}{2}*2*3=12-2-2-3=5$ units squared

Thus, the areas are equal.

8 0

1 year ago

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Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

adoni [48]

Step-by-step explanation

<h3>Prerequisites:</h3>

<u>You need to know: </u>

$b^2 - 4ac = 0 \Rightarrow 1 solution$

$b^2 - 4ac > 0 \Rightarrow 2 solutions$

$b^2 - 4ac < 0 \Rightarrow No\ real\ solutions$

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$2x^2-7x-9 = 0$

$b^2 - 4ac$

$-7^2 - 4(2)(-9) = 121$

2 Solutions

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$x^2-4x+4 = 0$

$b^2 - 4ac$

$-4^2 - 4(1)(4) = 0$

1 Solution

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$4x^2-3x-1 = 0$

$b^2 - 4ac$

$-3^2 - 4(4)(-1) = 25$

2 Solutions

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$x^2-2x-8 = 0$

$b^2 - 4ac$

$-2^2 - 4(1)(-8) = 36$

2 Solutions

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$3x^2+5x+3 = 0$

$b^2 - 4ac$

$5^2 - 4(3)(3) = -11$

No Solutions

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3 0

2 years ago

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On a coordinate plane, square P Q R S is shown. Point P is at (4, 2), point Q is at (8, 5), point R is at (5, 9), and point S is

sergey [27]

Answer:

(D)The midpoint of both diagonals is (4 and one-half, 5 and one-half), the slope of RP is 7, and the slope of SQ is Negative one-sevenths.

Step-by-step explanation:

Point P is at (4, 2),
Point Q is at (8, 5),
Point R is at (5, 9), and
Point S is at (1, 6)

Midpoint of SQ $=\frac{1}{2}(1+8,5+6)=(4.5,5.5)$

Midpoint of PR $=\frac{1}{2}(4+5,2+9)=(4.5,5.5)$

Now, we have established that the midpoints (point of bisection) are at the same point.

Two lines are perpendicular if the slope of one is the negative reciprocal of the other.

In option D

Slope of RP =7

Slope of SQ $=-\dfrac17$

Therefore, lines RP and SQ are perpendicular.

Option D is the correct option.

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2 years ago

The fastest lion ever recorded ran approximately 402 meters in 18 seconds. Which expression shows how to correctly determine the

MaRussiya [10]

Answer

402 meters ÷ 18 seconds

Step-by-step explanation:

7 0

2 years ago

the daily production cost, c, for x units is modeled by the equation: c = 200 – 7x 0.345x2 explain how to find the domain and ra

jenyasd209 [6]

C(x) = 200 - 7x + 0.345x^2

Domain is the set of x-values (i.e. units produced) that are feasible. This is all the positive integer values + 0, in case that you only consider that can produce whole units.

Range is the set of possible results for c(x), i.e. possible costs.

You can derive this from the fact that c(x) is a parabole and you can draw it, for which you can find the vertex of the parabola, the roots, the y-intercept, the shape (it open upwards given that the cofficient of x^2 is positive). Also limit the costs to be positive.

You can substitute some values for x to help you, for example:

x y
0 200
1 200 -7 +0.345 = 193.345
2    200 - 14 + .345 (4) = 187.38
3 200 - 21 + .345(9) = 182.105
4    200 - 28 + .345(16) = 177.52
5    200 - 35 + 0.345(25) = 173.625
6    200 - 42 + 0.345(36) = 170.42

10 200 - 70 + 0.345(100) =164.5
11 200 - 77 + 0.345(121) = 164.745

The functions does not have real roots, then the costs never decrease to 0.

The function starts at c(x) = 200, decreases until the vertex, (x =10, c=164.5) and starts to increase.

Then the range goes to 164.5 to infinity, limited to the solutcion for x = positive integers.

6 0

2 years ago

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