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VLD [36.1K]
2 years ago
15

Dave walked to his friend's house at a rate of 4 mph and returned back biking at a rate of 10 mph. If it took him 18 minutes lon

ger to walk than to bike, what was the total distance of the round trip?
I need help on it
Mathematics
1 answer:
katrin [286]2 years ago
6 0

Answer:

4 miles

Step-by-step explanation:

<u>Walking:</u>

Distance  = d miles

Rate = 4 mph

Time = t hours

d=4\cdot t

<u>Biking:</u>

Distance = d miles

Rate = 10 mph

Time =t-\dfrac{18}{60}=t-0.3 hours (convert minutes to hours)

d=10\cdot (t-0.3)

Hence,

4t=10(t-0.3)\\ \\4t=10t-3\\ \\4t-10t=-3\\ \\-6t =-3\\ \\6t=3\\ \\t=\dfrac{3}{6}=\dfrac{1}{2}=0.5\ hour

Therefore, the distance to friend's house is

d=4\cdot 0.5=2\ miles

and the total distance of the round trip is

2+2=4\ miles

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