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SIZIF [17.4K]
2 years ago
6

Mike's Bikes has mountain bikes that usually sell for $275 on sale for $220. Mike used this ratio to find the percent change. Is

he correct? Explain.
Mathematics
2 answers:
MrRa [10]2 years ago
4 0

No. Mike wrote the ratio as the amount of change to the new amount. He should have used the ratio of the amount of change to the original amount, which is 55

55/275 , or 20%.

zhannawk [14.2K]2 years ago
4 0
20%
220 divided by 275 to get .8 
80% then 80% minus 100%
=20%
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Let x stand for the length of an individual screw. 100 screws were sampled at a time. The population mean is 2.5 inches and the
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Answer:

The mean is defining the average length(2.5in) of the 100 measured screws.

Step-by-step explanation:

The mean is usually calculated in order to determine the average of a set of values.

8 0
2 years ago
Orange M&M’s: The M&M’s web site says that 20% of milk chocolate M&M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
2 years ago
write a number from 20 to 50 that has both tens and ones. use pictures and words to show the tens and ones.
slavikrds [6]
The answer is 35 because it in beetween 20 and 50

5 0
2 years ago
Read 2 more answers
$5000 was invested into an investment that pays 4.25% simple interest. The total value of the investment amounted to $6593.75. H
Basile [38]

Answer:

7.5 years

Step-by-step explanation:

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R = 4.25%,

A = $6593.75,

N =?

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\because \: SI = \frac{ PNR}{100} \\  \\  \therefore \: 1593.75 =  \frac{5000 \times N \times 4.25}{100}  \\  \\  \therefore \: 1593.75 \times 100 = 21,250 \times N \\  \\ N =  \frac{159375}{21250}  \\  \\ N = 7.5 \: years \:

6 0
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77/65=1.18
round 1.18 to 1.2
6 0
2 years ago
Read 2 more answers
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