answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
deff fn [24]
2 years ago
12

Anika wants to determine The maximum number of tulip bulbs (T) she can purchase if each bulb costs $1.50. She will also need to

purchase separate pots for each bulb at $1.25 each and a bag of potting soil for $10. Set up an inequality to determine how many tulip bulbs Anika can purchase without spending more than $20, and solve it. Can Anika by exactly enough bulbs in pots to spend the full $20 explain can you think of a better inequality to describe the answer
Mathematics
2 answers:
Advocard [28]2 years ago
7 0

The <em>correct inequality</em> is:

1.50T + 1.25T + 10 ≤ 20

The <em>correct solution</em> is:

T ≤ 3; no, she cannot spend the entire $20.

Explanation:

T is the number of tulip bulbs she buys. Each bulb costs $1.50; this gives the expression 1.50T.

She will buy the same number of pots as bulbs, since she needs a pot for each bulb. Each pot is $1.25; this gives the expression 1.25T.

Adding the $10 for potting soil to this, we have 1.50T+1.25T+10. She can spend no more than $20; this means she can spend less than or equal to 20. This gives us the inequality:

1.50T+1.25T+10 ≤ 20

To solve this, first combine like terms:

2.75T + 10 ≤ 20

Subtract 10 from each side:

2.75T+10-10 ≤ 20-10

2.75T ≤ 10

Divide each side by 2.75:

2.75T/2.75 ≤ 10/2.75

T ≤ 3.64

She cannot buy a partial bulb or pot, so the answer is then T ≤ 3. If she buys the same number of pots as she does bulbs, there is no way she can spend the entire $20.

PtichkaEL [24]2 years ago
6 0
T( 1.50+ 1.25) + 10.00 < 20.00 2.75t + 10.00 < 20.00 2.75t < 10.00 T < 3.63 Partial bulbs and puts can't be bought, so Anika cannot spent the full $20.00. Therefore, t < 3 if t can be a whole number.
You might be interested in
Find the sum of the first 8 terms of the sequence: -5. 15, -45, 135, .......
MakcuM [25]
Sum of geometric sequence

for the sum where the initial value is a₁ and the common ratio is r and the term is n

S_n= \frac{a_1(1-r^n)}{1-r}

common ratio is -3
-5 times -3 is 15, -15 times -3=-45 etc
first term is -5
and we want the 8th term

S_8= \frac{-5(1-(-3)^8)}{1-(-3)}
S_8= \frac{-5(1-6561)}{1+3}
S_8= \frac{-5(-6560)}{4}
S_8= \frac{32800}{4}
S_8= 8200


the sum is 8200
7 0
1 year ago
JL has coordinates J(-6, 1) and L(-4,3).<br> Find the coordinates of the midpoint.
ikadub [295]

Answer:

The coordinates of the mid-point of JL are (-5 , 2)

Step-by-step explanation:

If point (x , y) is the mid-point of a segment whose end-points are (x_{1},y_{1}) and (x_{2},y_{2}), then x=\frac{x_{1}+x_{2}}{2} and  y=\frac{y_{1}+y_{2}}{2}

∵ JL is a segment

∵ The coordinates of J are (-6 , 1)

∴  x_{1} = -6 and  y_{1} = 1

∵ The coordinates of L are (-4 , 3)

∴  x_{2} = -4 and  y_{2} = 3

Lets use the rule above to find the mid-point of JL

∵ x=\frac{-6+-4}{2}=\frac{-10}{2}

∴ x = -5

∴ The x-coordinate of the mid-point is -5

∵ y=\frac{1+3}{2}=\frac{4}{2}

∴ y = 2

∴ The y-coordinate of the mid-point is 2

∴ The coordinates of the mid-point of JL are (-5 , 2)

5 0
2 years ago
Merle Fonda opened a new savings account. She deposited $40,000 at 10% compounded semiannually. At the start of the fourth year,
IrinaVladis [17]
Use compound interest formula  F=P(1+i)^n twice, one for each deposit and sum the two results.

For the P=$40,000 deposit,
i=10%/2=5%  (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253

For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6 
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913

Total amount after 6 years
= 71834.253 + 26801.913
=98636.17   (to the nearest cent.)
8 0
1 year ago
ALGEBRA 2/ TRIG QUESTION ATTACHED Please help ❤️❤️
ss7ja [257]
Let's calculate the value of angle A and B

sin(A) =-4/5 → sin⁻¹(- 4/5) = A  →  A = - 53.13


cos(B) = -5/13 → cos⁻¹ (- 5/13) = B  → B = 112.62


tan (A+B) = sin(A+B)/cos(A+B)  with A+B = -53.13 + 112.62 = 59.49

tan (A+B) = sin(59.49)/cos(59.49) = 0.86154/0.507688 = 1.6969.

(Answer H = 56/33 = 1.6969)

7 0
2 years ago
Suppose that 20% of the adult women in the United States dye or highlight their hair. We would like to know the probability that
Rasek [7]

Answer:

71.08% probability that pˆ takes a value between 0.17 and 0.23.

Step-by-step explanation:

We use the binomial approxiation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.2, n = 200. So

\mu = E(X) = np = 200*0.2 = 40

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{200*0.2*0.8} = 5.66

In other words, find probability that pˆ takes a value between 0.17 and 0.23.

This probability is the pvalue of Z when X = 200*0.23 = 46 subtracted by the pvalue of Z when X = 200*0.17 = 34. So

X = 46

Z = \frac{X - \mu}{\sigma}

Z = \frac{46 - 40}{5.66}

Z = 1.06

Z = 1.06 has a pvalue of 0.8554

X = 34

Z = \frac{X - \mu}{\sigma}

Z = \frac{34 - 40}{5.66}

Z = -1.06

Z = -1.06 has a pvalue of 0.1446

0.8554 - 0.1446 = 0.7108

71.08% probability that pˆ takes a value between 0.17 and 0.23.

6 0
2 years ago
Other questions:
  • For each babysitting job, Tamar charges $6 for bus fare plus $8 per hour. She only accepts babysitting jobs if the total charge
    7·2 answers
  • Suppose your club is selling candles to raise money. It cost $100 to rent a booth from which to sell the candles. If the candles
    8·2 answers
  • Ari mixed 2 1/4 cups of red grapes with 1/2 cups of green grapes. He then divided the grapes into bags with 3/4 cup of mixed gra
    6·2 answers
  • Which of the following shows the prime factorization of 36 using exponential notation?
    6·1 answer
  • Tommy has 5 jars of marbles. Each jar is 2/3 filled with marbles. How many jars of marbles does Tommy have
    5·1 answer
  • Kyra and her twin sister share shoes. In there closet they have four pairs of Sandals,five pairs of tennis shoes, and three pair
    5·1 answer
  • wingspans of adult herons have approximate normal distribution with mean 125cm and a standard deviation 12cm. what proportion of
    13·1 answer
  • A certain type of thread is manufactured with a mean tensile strength of 78.3 kilograms and a standard deviation of 5.6 kilogram
    15·1 answer
  • A 100-gallon barrel, initially half-full of oil, develops a leak at the bottom. Let A(t) be the amount of oil in the barrel at t
    14·1 answer
  • Write (9m)^4 without exponents.
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!