Step-by-step explanation:
a.) To model this scenario
Let the height of ball = y
The height of 1st= 0.5y
2nd =0.5(0.5y)
3rd = 0.5*(0.5(0.5y))
Hence the height of nth bounce can be modeled as
Height of nth bounce =(0.5ⁿ-1)*y
The exponential equation is
hn= (0.5ⁿ-1)*y
b.) if the ball is dropped from 9ft above the ground
y= 9ft
On the 4th bounce
n=4
Substituting in the exponential equation we have
h4=(0.5^4-1)*9
h4=0.5³*9
h4= 0.125*9
h4= 1.125ft
On the 4th bounce, the ball will reach a height of 1.125ft
Well, since it only asking about the product, you don't have to multiply the result
The product would be :
3 x 2 = 6
3x 20 = 3 x 2 x 10 = 60
3 x 200 = 3 x 2 x 10 x 10 = 600
hope this helps
Part A) means that we have to find a composition of functions A and m
A(m(t))=π(9t)²=9πt²
part B)
A(m(t))=9πt²
A(m(2))=9*3.14*(2)²=113.04
Answer:
am i supposed to do area? volume? circumfrence?
The houses can be placed in 362,880 ways.
<u>Step-by-step explanation:</u>
The 9 houses are each in different design.
The each lot can place any of the 9 houses.
- The 1st lot can place anyone house of all the 9 houses.
- The 2nd lot can place one of remaining 8 houses.
- The 3rd lot can place one of remaining 7 houses.
Similarly, the process gets repeated until the last house is placed on a lot.
<u>From the above steps, it can be determined that :</u>
The number of ways to place the 9 houses in 9 lots = 9!
⇒ 9×8×7×6×5×4×3×2×1
⇒ 362880 ways.
Therefore, the houses can be placed in 362880 ways.
