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Julli [10]
2 years ago
15

-6y + 3(12y) = 20(y - 1) + 15 is it true?

Mathematics
1 answer:
xxMikexx [17]2 years ago
5 0

Answer:

y= - 1/2 (negative half) =  -0.5

Step-by-step explanation:

−6y+3(12y)=20(y−1)+15

Multiply 3 and 12 to get 36.

−6y+36y=20(y−1)+15

Combine −6y and 36y to get 30y.

30y=20(y−1)+15

Use the distributive property to multiply 20 by y−1.

30y=20y−20+15

Add −20 and 15 to get −5.

30y=20y−5

Subtract 20y from both sides.

30y−20y=−5

Combine 30y and −20y to get 10y.

10y=−5

Divide both sides by 10

y= -5/10

Reduce the fraction -5/10 = -0.5 to lowest terms by extracting and cancelling out 5 .

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The triangles shown below must be congruent. True or false
Alex777 [14]
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4 0
2 years ago
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An isosceles triangle ABC with the base BC is inscribed in a circle. Find the measure of angles of it, if measure of arc BC = 10
Usimov [2.4K]

Answer:

The measures of the angles of the triangle are 51° , 64.5° , 64.5°

OR

The measures of the angles of the triangle are 129° , 25.5° , 25.5°

Step-by-step explanation:

* Lets explain the meaning of the inscribed triangle in a circle

- If a triangle inscribed in a circle, then the vertices of the triangle lie

 on the circumference of the circle and each vertex is an inscribed

 angle in the circle subtended by the opposite arc

- Fact in the circle the measure of the inscribed angle is 1/2 the

 measure of its subtended arc

* Now lets solve the problem

- Δ ABC is an isosceles with the base BC

∴ AB = AC

∴ m∠B = m∠C

- Δ ABC is inscribed in a circle

∴ ∠A is inscribed angle subtended by arc BC (minor or major)

# The measure of the minor arc is less than 180° and the measure of

  the major arc is greater then 180° and the sum of the two arcs

  equals the measure of the circle which is 360°

∴ ∠B subtended by arc AC

∴ ∠C subtended by arc AB

∵ The measure of the arc BC = 102°

- There is two cases in this question

(1) If the angle A subtended by the minor arc BC

(2) If the angle A subtended by the major arc BC

- Lets solve case (1)

∵ ∠A is an inscribed angle subtended by the minor arc BC

∴ m∠A = 1/2 the measure of the arc BC

∵ The measure of the arc BC is 102°

∴ m∠A = 1/2 × 102 = 51°

∵ The sum of the measures of the interior angles of a triangle is 180°

∴ m∠A + m∠B + m∠C = 180°

∴ 51 + m∠B + m∠C = 180° ⇒ subtract 51 from both sides

∴ m∠B + m∠C = 129°

∵ m∠B = m∠C ⇒ isosceles Δ

∴ m∠B = m∠C = 129/2 = 64.5°

* The measures of the angles of the triangle are 51° , 64.5° , 64.5°

- Lets solve case (2)

∵ ∠A is an inscribed angle subtended by the major arc BC

∴ m∠A = 1/2 the measure of the arc BC

∵ The measure of the minor arc BC is 102°

∵ The measure of the circle is 360°

∴ The measure of the major arc = 360 - 102 = 258°

∴ m∠A = 1/2 × 258 = 129°

∵ The sum of the measures of the interior angles of a triangle is 180°

∴ m∠A + m∠B + m∠C = 180°

∴ 129 + m∠B + m∠C = 180° ⇒ subtract 129 from both sides

∴ m∠B + m∠C = 51°

∵ m∠B = m∠C ⇒ isosceles Δ

∴ m∠B = m∠C = 51/2 = 25.5°

* The measures of the angles of the triangle are 129° , 25.5° , 25.5°

4 0
2 years ago
Solve the equation a. 0.76, –0.76 c. 3.87 b. 4.98 d. 1.53, –1.53 Please select the best answer from the choices provided A B C D
lord [1]

You didn't write the equation you like to be solved. It is clear though, from the options you gave, that there are two equations you want to be solved simultaneously. I will give an example to illustrate this, and you may apply the process in solving your problem.

Step-by-step explanation:

Let

x + y = 7 ....................................(1)

x - 2y = -2...................................(2)

SOLVING USING THE SUBSTITUTION METHOD.

From (1), make y the subject.

y = 7 - x ....................................(3)

Substitute the value of y in (3) into (2)

x - 2(7 - x) = -2

x - 14 + 2x = -2

x + 2x = -2 + 14

3x = 12

Divide both sides by 3

x = 12/3 = 4

Now use x = 4 in (3)

y = 7 - 4 = 3

Therefore, ( x, y) = (4, 3)

SOLVING USING THE ELIMINATION METHOD.

x + y = 7 ....................................(1)

x - 2y = -2...................................(2)

First, let us eliminate x by subtracting (2) from (1)

(x + y) - (x - 2y) = 7 - (-2)

y + 2y = 7 + 2

3y = 9

Divide both sides by 3

y = 9/3 = 3

To eliminate y, first multiply (1) by 2, and add the result to (1)

2 × (1): 2x + 2y = 14 ........................(3)

................x - 2y = -2.........................(2)

____________________

...............3x = 12

............... x = 12/3 = 4

Therefore (x, y) = (4, 3)

7 0
2 years ago
Read 2 more answers
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djyliett [7]
$160

.20 * 200= 40

200-40=160
4 0
2 years ago
Read 2 more answers
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