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2 years ago

For what values (cases) of the variables the expression does not exist: a/2x−4 (That equation is a fraction)

Mathematics

1 answer:

Dmitry_Shevchenko [17]2 years ago

3 0

Answer:

When x=2 the expression is undefined

Step-by-step explanation:

When the denominator is zero, the expression is undefined

2x-4 =0

2x=4

x=4/2

x=2

When x=2 the expression is undefined

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A pet store donated 50 pounds of food for adult dogs, puppies, and cats to an animal shelter. 19 and 3/4 pounds was adult dog fo

Sati [7]

So first we will add together the fractions. 3/4 is equal to 6/8, so we will add 6/8 to 7/8 and get 13/8, or 1 5/8. Then we can add together the whole numbers, 19 and 18, to get 37. Then add 37 + 1 5/8 and get 38 5/8. Lastly, we subtract that amount from 50 to get a finale number of 11 3/8. The pet store donated 11 3/8 pounds of cat food! Hope this helps!

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1 year ago

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A town has two shopping malls. A survey conducted on the shopping preferences of the town's residents showed that 62% of the res

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Step-by-step explanation:

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2 years ago

Amy hiked 3.25 miles farther than Meng. Amy hiked 7 miles. Which equation can be used to find the number of miles, x, Meng hiked

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Let distance covered by Meng be 'x' (given)

x+3.25=7

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2 years ago

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Find the area of the part of the plane 5x + 4y + z = 20 that lies in the first octant.

BlackZzzverrR [31]

This part of the plane is a triangle. Call it $\mathcal S$ . We can find the intercepts by setting two variables to 0 simultaneously; we'd find, for instance, that $y=z=0$ means $5x=20\implies x=4$ , so that (4, 0, 0) is one vertex of the triangle. Similarly, we'd find that (0, 5, 0) and (0, 0, 20) are the other two vertices.

Next, we can parameterize the surface by

$\mathbf s(u,v)=\langle4(1-u)(1-v),5u(1-v),20v\rangle$

so that the surface element is

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=20\sqrt{42}(1-v)\,\mathrm du\,\mathrm dv$

Then the area of $\mathcal S$ is given by the surface integral

$\displaystyle\iint_{\mathcal S}\mathrm dS=20\sqrt{42}\int_{u=0}^{u=1}\int_{v=0}^{v=1}(1-v)\,\mathrm dv\,\mathrm du$
$\displaystyle=20\sqrt{42}\int_{v=0}^{v=1}(1-v)\,\mathrm dv=10\sqrt{42}\approx64.8074$

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2 years ago

How do you use a number line to solve 235+123

Novosadov [1.4K]

<span>Number line refers to a mathematical process of solving the equation with the use of lines.
=> 235 + 123
Starting from 0 you count 1 up to 235. Then starting from 235 you additionally count another 123.
Then from zero start counting the total number to the line you stopped when adding 123 to 235.

This simply equals to
=> 235 + 123
=> 358.
Pls. see attached image for illustration of number line.</span>Answer here

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2 years ago