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kipiarov [429]
1 year ago
7

You wanted to join a booth fair, and you are aiming to get a profit that is twice as

Mathematics
1 answer:
sashaice [31]1 year ago
8 0

You wanted to join a booth fair, and you are aiming to get a profit that is twice as  your capital. Using the given information, your sample plan may be as follows:

Product                   Organic skincare products for women

Description             An organic skincare cream and soap that brightens

                                 and moisturizes your skin.

Goal                          To provide anti-aging skin for women and

                                  maintaining  their skin body.

Capital                      15000

Fixed Cost                  7000

Variable Cost             8000

Profit function            300(a) = 450a - 150a

To prove that the profit function will yield twice the capital.

This profit function: 300(y) = 450y - 150y will help achieve twice profit as your capital.

Profit function = revenue function r(y) - cost function c(y)

300(y) = 450y - 150y

where;

  • y = no of units produced and sold.
  • p = profit sold per unit

Cost function C(y) = fixed cost + (variable cost) × (amount of unit sold)

Assumption:

Cost function C(y) = 7000 + (80 × 100)

Cost function C(y) = 7000 + 8000

Cost function C(y) = 15000

Revenue function R(y) = price per revenue sold × no of sold units

R(y) = 450 × 100

R(y) = 45000

∴

Profit function = 45000 - 15000

Profit function = 30000

Therefore, can conclude that the profit function is revenue function r(y) - cost function c(y).

Hence the formula:

Profit function = revenue function r(y) - cost function c(y)   (Proved)

Learn more about Profit function here:

brainly.com/question/16866047?referrer=searchResults

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Felicia wanted to find the number of boys in the school band if 30% of the 50 students are boys. Is her answer correct? Explain
docker41 [41]

Answer:

Creo que con 15

Step-by-step explanation:

50 -------> 100%

X ---------> 30%

X = (50*30)/100

X= 15 boys

4 0
1 year ago
Read 2 more answers
Darcie wants to crochet a minimum of 3 blankets blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 of a
bearhunter [10]

Answer:

The inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal is:

s\leq 15

Thus, Darcie can skip a maximum of 15 days.

Step-by-step explanation:

Question

Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 of a blanket per day. She has 60 days until when she wants to donate the blankets, but she also wants to skip crocheting some days so she can volunteer in other ways. Write an inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal.

Given:

Darcie has a target to crochet a minimum of 3 blankets.

Rate at which Darcie crochets = \frac{1}{15} of a blanket per day.

Darcie has 60 days to crochet the blankets

To write an inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal.

Solution:

The number of days Darcie can skip crocheting is represented by s

So, number of days left for Darcie to crochet = 60-s

In 1 day Darcie crochets  \frac{1}{15} of a blanket.

So, in (60-s) days she will crochet = \frac{1}{15}(60-s)  blankets.

Her aim is to crochet at least 3 blankets.

Thus, the inequality can be given as:

\frac{1}{15}(60-s)\geq 3

Solving for s

Multiplying both sides by 15 to remove fractions.

15\times\frac{1}{15}(60-s)\geq 3\times 15

60-s\geq 45

Subtracting both sides by 60.

60-60-s\geq 45-60

-s\geq -15

Dividing both sides by -1.

\frac{-s}{-1}\leq \frac{-15}{-1}     [ On dividing by negative number the sign of the inequality is reversed]

∴ s\leq 15

Thus, Darcie can skip a maximum of 15 days.

3 0
1 year ago
Read 2 more answers
Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The
abruzzese [7]

The question is incorrect.

The correct question is:

Three TAs are grading a final exam.

There are a total of 60 exams to grade.

(c) Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The TAs grade at different rates, so the first TA will grade 25 exams, the second TA will grade 20 exams and the third TA will grade 15 exams. How many ways are there to distribute the exams?

Answer: 60!/(25!20!15!)

Step-by-step explanation:

The number of ways of arranging n unlike objects in a line is n! that is ‘n factorial’

n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1

The number of ways of arranging n objects where p of one type are alike, q of a second type are alike, r of a third type are alike is given as:

n!/p! q! r!

Therefore,

The answer is 60!/25!20!15!

6 0
1 year ago
On the first day of a family road trip, Kai's family travels 365 miles.
Gekata [30.6K]
They traveled 292 miles on day two.

Known: On the first day they traveled 365 and on the second they traveled 20% less.

Solution:

If they traveled 20% less on the second day, that means they traveled 80% of the distance they traveled the first day.

365 miles * .8 = 292.

You could also solve this as:
20% of 365 is 73 miles
365 * .2 = 73.
So they traveled 73 less miles on the second day.
365 miles on the first day - 73 miles less on the second day = 292 miles.

I hope this helps!
7 0
1 year ago
Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One common ch
enot [183]

Answer:

y=\frac{-7t^2+22t-7}{7t-22}

Step-by-step explanation:

We are given that

Initial value problem

y'=(t+y)^2-1, y(3)=4

Substitute the value z=t+y

When t=3 and y=4 then

z=3+4=7

y'=z^2-1

Differentiate z w.r.t t

Then, we get

\frac{dz}{dt}=1+y'

z'=1+z^2-1=z^2

z^{-2}dz=dt

Integrate on both sides

-\frac{1}{z}dz=t+C

z=-\frac{1}{t+C}

Substitute t=3 and z=7

Then, we get

7=-\frac{1}{3+C}

21+7C=-1

7C=-1-21=-22

C=-\frac{22}{7}

Substitute the value of C then we get

z=-\frac{1}{t-\frac{22}{7}}

z=\frac{-7}{7t-22}

y=z-t

y=\frac{-7}{7t-22}-t

y=\frac{-7-7t^2+22t}{7t-22}

y=\frac{-7t^2+22t-7}{7t-22}

8 0
2 years ago
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