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2 years ago

You wanted to join a booth fair, and you are aiming to get a profit that is twice as

Mathematics

1 answer:

sashaice [31]2 years ago

8 0

You wanted to join a booth fair, and you are aiming to get a profit that is twice as your capital. Using the given information, your sample plan may be as follows:

Product Organic skincare products for women

Description An organic skincare cream and soap that brightens

and moisturizes your skin.

Goal To provide anti-aging skin for women and

maintaining their skin body.

Capital 15000

Fixed Cost 7000

Variable Cost 8000

Profit function 300(a) = 450a - 150a

To prove that the profit function will yield twice the capital.

This profit function: 300(y) = 450y - 150y will help achieve twice profit as your capital.

Profit function = revenue function r(y) - cost function c(y)

300(y) = 450y - 150y

where;

y = no of units produced and sold.
p = profit sold per unit

Cost function C(y) = fixed cost + (variable cost) × (amount of unit sold)

Assumption:

Cost function C(y) = 7000 + (80 × 100)

Cost function C(y) = 7000 + 8000

Cost function C(y) = 15000

Revenue function R(y) = price per revenue sold × no of sold units

R(y) = 450 × 100

R(y) = 45000

∴

Profit function = 45000 - 15000

Profit function = 30000

Therefore, can conclude that the profit function is revenue function r(y) - cost function c(y).

Hence the formula:

Profit function = revenue function r(y) - cost function c(y) (Proved)

Learn more about Profit function here:

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2 years ago

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A hole is drilled in a sheet-metal component, and then a shaft is inserted through the hole. The shaft clearance is equal to dif

VashaNatasha [74]

Answer:

(A)

$P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192$

(B)

Then the cumulative function would be

$CF(x) = 1.25x - 0.25x^5$ if 0<x<1

0 otherwise.

Step-by-step explanation:

(A)

We are looking for the probability that the random variable X is greater than 0.8.

$P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192$

(B)

For any $x$ you are looking for the probability $P(X \geq x)$ which is

$P(X \geq x) = \int\limits_{-\infty}^{x} 1.25(1-t^4) dt = \int\limits_{0}^{x} 1.25(1-t^4) dt = 1.25x - 0.25x^2$

Then the cumulative function would be

$CF(x) = 1.25x - 0.25x^5$ if 0<x<1

0 otherwise.

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2 years ago

The coordinate values of the vertices of △klm are integers. triangle klm has vertices located at (1, 1), (5, 4) and (5, 1). whic

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The rest of the queastion is :
 A) (-1, 1), (-1, 4), (2, 1)
B) (0, 0), (3, 4), (0, 5)
C) (-1, 1), (-4, 5), (-1, 5)
D) (0, 0), (-5, 0), (0, 4)
==============================

The distance between two points (x₁,y₁),(x₂,y₂) = d
$d = \sqrt{ (x2-x1)^{2} + (y2-y1)^{2} }$

we have K(1, 1), L(5, 4) and M(5, 1)
we will find the length between each two points.
KL = $d = \sqrt{ (5-1)^{2} + (4-1)^{2} }$ = 5
LM = $d = \sqrt{ (5-5)^{2} + (1-4)^{2} }$ = 3
KM = $d = \sqrt{ (5-1)^{2} + (1-1)^{2} }$ = 4

now check each group from the choices
the group that will give the same result will be the correct choice.
The correct choice is C
C) (-1, 1), (-4, 5), (-1, 5)

check the answer;
K'(-1, 1), L'(-4, 5), M'(-1, 5)

K'L' = $d = \sqrt{ (-4+1)^{2} + (5-1)^{2} }$ = 5
L'M' = $d = \sqrt{ (-1+4)^{2} + (5-5)^{2} }$ = 3
K'M' = $d = \sqrt{ (-1+1)^{2} + (5-1)^{2} }$ = 4

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2 years ago

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Answer:

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Step 1
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height=4 units
volume square box=100*4----> 400 units³

step 2
volume rectangular box=2*volume square box
volume rectangular box=2*400------> 800 units³

volume rectangular box=L*W*H
H=5 units
W=10 units
Volume=800 units³
800=L*10*5------> solve for L
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the answer is
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