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ZanzabumX [31]
2 years ago
14

Line segments XY and ZY are tangent to circle O. Circle O is shown. Triangle X Y Z has points X and Z on the circle. Lines X Y a

nd Z Y are tangents that intersect at point Y outside of the circle. Which kind of triangle must triangle XYZ be? an equilateral triangle an isosceles triangle a scalene triangle a right triangle
Mathematics
1 answer:
pickupchik [31]2 years ago
4 0

Answer:

The correct option is;

An isosceles triangle

Step-by-step explanation:

The parameters given are;

Line segments XY and ZY are tangents to circle O.

ΔXYZ has points X and Z on the circle.

XY and ZY are tangents that intersect at point Y outside the circle'

Therefore, given the circle has center O, then;

OY ≅ OZ = Radius of circle with center O

∠OXY ≅ ∠OZY = 90°  (The radius line from the circle center to the tangent point is perpendicular)

OY ≅ OY (Reflexive property)

ΔOYX and ΔOYZ are right triangles (Triangle with one angle = 90°

ΔOYX ≅ ΔOYZ (Hypotenuse Leg, HL, rule of congruency)

Therefore;

XY = ZY (Corresponding Parts of Congruent Triangles are Congruent CPCTC)

Triangle XYZ is an isosceles triangle (Triangle with two equal sides).

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Point Z is equidistant from the vertices of ΔTUV.
nadya68 [22]

Answer:

option C. Angle BTZ Is-congruent-to Angle BUZ

Step-by-step explanation:

Point Z is equidistant from the vertices of triangle T U V

So, ZT = ZU = ZV

When ZT = ZU  ∴ ΔZTU is an isosceles triangle ⇒ ∠TUZ=∠UTZ

When ZT = ZV  ∴  ΔZTV is an isosceles triangle ⇒ ∠ZTV=∠ZVT

When ZU = ZV  ∴ ΔZUV is an isosceles triangle ⇒ ∠ZUV=∠ZVU

From the figure ∠BTZ is the same as ∠UTZ

And ∠BUZ is the same as ∠TUZ

So, the statement that must be true is option C

C.Angle BTZ Is-congruent-to Angle BUZ

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