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sasho [114]
2 years ago
8

Rectangle ABCD with coordinates A(1,1), B(4,1), C(4,2) and D(1,2) dilates with respect to the origin to give rectangle A’B’C’D’.

If A’B’=6 what is the scale factor of the dilation?
A: 6
B: 3
C: 2
D: 1/2
E: 4
Mathematics
2 answers:
Delvig [45]2 years ago
8 0

Answer: Option C.

Step-by-step explanation:

You need to find the distance AB with the formula for calculate the distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Then, substituting the coordinates of the points A(1,1) and B(4,1), you get:

AB=\sqrt{(4-1)^2+(1-1)^2}=3

You know that A'B'=6, then the scale factor of dilation can be calculated with:

k=\frac{A'B'}{AB}

Substituting values, you get:

k=\frac{6}{3}\\\\k=2

This matches with the option C.

finlep [7]2 years ago
7 0

C should be the answer

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yan [13]

Answer:

33%

Step-by-step explanation:

3 0
1 year ago
The blue M&M was introduced in 1995. Before then, the color mix in a bag of plain M&Ms was (30% Brown, 20% Yellow, 20% R
IRISSAK [1]

Answer:

The probability that the yellow M&M came from the 1994 bag is 0.07407 or 7.407%

Step-by-step explanation:

Given

Before 1995

(Br) Brown = 30%

(Y) Yellow = 20%  =0.2

(R) Red = 20%

(G) Green =10%  =0.1

(O) Orange = 10%

(T) Tan = 10%

 

After 1995

(Br) Brown = 13%

(Y) Yellow = 14%  =0.14

(R) Red = 13%

(G) Green = 20% = 0.2

(O) Orange = 16%

(Bl) Blue = 24%

Since there are two bags, let A be the bag from 1994, and B be the bag from 1996

Then let AY imply we drew a yellow M&M from the 1994 bag

AG implies we drew a green M&M from the 1994 bag

BY implies imply we drew a yellow M&M from the 1996 bag

BG implies we drew a green M&M from the 1996 bag

P(AY) =0.2

P (BY) = 0.14

P(AG) =0.1

P(BG) =0.2

Since the draws from the 1994 and 1996 bag are independent,

therefore

P(AY n BG) = 0.2 * 0.2 = 0.04  -------(1)\\P(AG n BY) =0.1 * 0.14 =0.014   --------(2)\\

The draws can happen in either of the 2 ways in (1) and (2) above

therefore total probability E is given as

E =P( AY n BG) u P(AG n BY)\\=0.04 + 0.014 =0.O54

For the yellow one to be from 1994, it implies that the event to be chosen is

P(AYnBG) = 0.2*0.2

Since the total probability is given as E=0.054

then P((AYnBG) /E) =\frac{0.04}{0.054} = 0.07407

Concluding statement: This is the condition for the Yellow one to come from 1994 and green from 1996 provided that they obey the condition from E

4 0
2 years ago
Write the equation of the line fully simplified slope-intercept form.​
FinnZ [79.3K]

Answer:

y=-4/10x+ 5 or y=-0.4x+5

Step-by-step explanation:

The formula for slope is y=mx+b. The "m" is the slope, the "x" is constant, and "b" is your y-intercept.

1. Figure out your slope:

Easiest way to do this is by using rise/run. You. take your point to the left and count how many spaces up or down it is from the second point, and then repeat that across the x-axis.

2. Determine whether it is positive or negative

A line with a positive slope is going to be angled upward and a line with a negative slope will be angled downward

3. Find the y-intercept

Simply look at the graph and find where the line crosses the y-axis

4. Plug everything into the equation

Once you do Steps 1-3, just plug everything in and you're done! If you have any questions, feel free to ask!

7 0
1 year ago
se the function to show that fx(0, 0) and fy(0, 0) both exist, but that f is not differentiable at (0, 0). f(x, y) = 9x2y x4 + y
alexandr1967 [171]

Answer:

It is proved that f_x, f_y exixts at (0,0) but not differentiable there.

Step-by-step explanation:

Given function is,

f(x,y)=\frac{9x^2y}{x^4+y^2}; (x,y)\neq (0,0)

  • To show exixtance of f_x(0,0), f_y(0,0) we take,

f_x(0,0)=\lim_{h\to 0}\frac{f(h+0,k+0)-f(0,0)}{h}=\lim_{h\to 0}\frac{\frac{9h^2k}{h^4+k^2}-0}{h}\\\therefore f_x(0,0)=\lim_{h\to 0}\frac{9hk}{h^4+k^2}=\lim_{h\to 0}\frac{9k}{h^3+\frac{k^2}{h}}=0    exists.

And,

f_y(0,0)=\lim_{k\to 0}\frac{f(h,k)-f(0,0)}{k}=\lim_{k\to 0}\frac{9h^2k}{k(h^4+k^2)}=\lim_{k\to 0}\frac{9h^2}{h^4+k^2}=\frac{9}{h^2}   exists.

  • To show f(x,y) is not differentiable at the origin cheaking continuity at origin be such that,

\lim_{(x,y)\to (0,0)}\frac{9x^2y}{x^4+y^2}=\lim_{x\to 0\\ y=mx^2}\frac{9x^2y}{x^4+y^2}=\frac{9x^2\times m x^2}{x^4+m^2x^4}=\frac{9m}{1+m^2}  where m is a variable.

which depends on various values of m, therefore limit does not exists. So f(x,y) is not continuous at (0,0). Hence it is not differentiable at (0,0).

4 0
2 years ago
How many 1.1 centimeters length can be made from a string that is 5.093 centimeters long ​
Lesechka [4]

Answer:

4

Step-by-step explanation:

    (whole string length) ÷ (1.1 cm pieces)

     5.093  ÷   1.1   =  <u>4</u>.63

                                           

         The answer, 4.63 is a whole number, 4, plus a remaninder of 63/100.

          The whole number part, the 4, is the answer.

                         

7 0
2 years ago
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