1) The outcomes for rolling two dice, the sample space, is as follows:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are 36 outcomes in the sample space.
2) The ways to roll an odd sum when rolling two dice are:
(1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5). There are 18 outcomes in this event.
3) The probability of rolling an odd sum is 18/36 = 1/2 = 0.5
Answer:
slope 3/5
Step-by-step explanation:
3x − 5y − 6 = 0
To find the slope, we want to solve for y
(y = mx+b slope intercept form of the equation(
Add 5y to each side
3x − 5y+5y − 6 = 0+5y
3x-6 = 5y
Divide by 5
3/5x -6/5 = 5y/5
3/5 x -6/5 = y
The slope is 3/5 and the y intercept is -6/5
Answer:
a. 52%
b. 40%
Step-by-step explanation:
Let A represents the event of raining on Monday and B represents the event of raining in Tuesday,
Then according to the question,
P(A) = 20% = 0.2,
P(B) = 40% = 0.4,
Here, A and B are independent events,
So, P(A∩B) = P(A) × P(B),
⇒ P(A∩B) = 0.2 × 0.4 = 0.08
We know that,
P(A∪B) = P(A) + P(B) - P(A∩B)
a. The probability it rains on Monday or Tuesday, P(A∪B) = 0.2 + 0.4 - 0.08
= 0.52
= 52%
b. The conditional probability it rains on Tuesday given that it rained on Monday,
