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1 year ago

MO, MN, and ON are the midsegments of △JKL. What is the perimeter of △JKL? 6 9.5 11.5 19

Mathematics

2 answers:

ipn [44]1 year ago

6 0

Answer is 19 just got it right

drek231 [11]1 year ago

6 0

the perimeter is 19

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Theresa has hired Chuck and Diana to paint a fence. Diana can paint 150 fence posts in the same time it takes Chuck to paint 130

Alenkasestr [34]

Answer: Chuck can paint 65 posts per hour.

Step-by-step explanation:

The data we have here is:

Diana can paint 150 fence posts in a time T

Chuck can pint 130 fence posts in a time T.

In one hour, Diana can paint 10 more fence posts than Chuck.

If D is the hourly rate of Daian, and C is the hourly rate for Chuck, we have:

D = 150/T

C = 130/T

D = C + 10

we can replace the last equation in the first one and geT:

C + 10 =150/T

C = 130/T

Now we can replace the bottom equation in the above one:

130/T + 10 = 150/T

10 = 150/T - 130/T = 20/T

T*10 = 20

T = 20/10 = 2

So T is 2 hours, then whe have:

D = 150post/2hours = 75 posts per hour.

C = 130 posts/2hours = 65 posts per hour.

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2 years ago

Given your sister's incomplete text,

egoroff_w [7]

Explanation:

Quadrants 2 and 3 houses points that have negative x-values, while as Quadrants 1 and 4 houses points that have positive x-values.

If 'your sister' completes the text with negative y-value, the point would be in Q3.

If 'your sister' completes the text with positive y-value, the point would be in Q2.

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2 years ago

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George tells you that when variables are in the denominator, the equation four over five plus three over x equals one over two b

jeka57 [31]

Answer
This explanation shows that the equation is solvable and there is not where in the steps we get a zero on the denominator.

Explanation
The equation given in the statement is;
4/5+3/x=1/2
This equation can be solved as follows:
4/5+3/x=1/2
3/x=1/2-4/5=(5-8)/10
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Taking the reciprocal on both side of the equation;
x/3=-10/3
Multiplying by 3 both sides we get;
x= -10

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1 year ago

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Leno4ka [110]

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$V = \pi r^2 h$