Antonio has just graduated from four years of college. For the last two years, he took out a Stafford loan to pay for his tuitio
n.
Each loan had a duration of ten years and interest compounded monthly. Antonio will pay each of them back by making
monthly payments, starting as he graduates. Antonio's loans are detailed in the table below.
Subsidized?
Year
Junior
Senior
Loan Amount ($)
5,894
5,258
Interest Rate (%)
6.9
7.5
Once all of his loans are paid off, what will Antonio's total lifetime cost be? Round all dollar values to the nearest bent.
a $16,246.80
b. $17,804.40
c. $7,593.16
d $9,874.76
Each loan had a duration of ten years and interest compounded monthly. Antonio will pay each of them back by making
monthly payments, starting as he graduates. Antonio's loans are detailed in the table below.
Subsidized?
Year
Junior
Senior
Loan Amount ($)
5,894
5,258
Interest Rate (%)
6.9
7.5
Once all of his loans are paid off, what will Antonio's total lifetime cost be? Round all dollar values to the nearest bent.
a $16,246.80
b. $17,804.40
c. $7,593.16
d $9,874.76
2 answers:
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Answer:
18.67% of bills are greater than $131
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What proportion of bills are greater than $131
This proportion is 1 subtracted by the pvalue of Z when X = 131. So
has a pvalue of 0.8133
1 - 0.8133 = 0.1867
18.67% of bills are greater than $131