To decrease it by 3% we need to fine 97% of it and 97% is the same as 0.97
16870 times 0.97=16363.9
16870 decreased by 3% is 16363.9
I hope I've helped!
Ahmed travel
miles in 5 days walking to school and back.
Step-by-step explanation:
Distance from house to school =
miles
Distance from school to house =
miles
Total distance in 1 day = 
Total distance in 1 day = 
Distance traveled in 5 days = 
Distance traveled in 5 days = 
Ahmed travel
miles in 5 days walking to school and back.
Keywords: fraction, addition
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#LearnwithBrainly
Answer:
The customer saves 5.9 - 5.5 = $0.5
when he shops at store B
Step-by-step explanation:
Stores A and B sells bananas at different prices per pound.
Bananas are being sold for $0.59 a pound at Store A and $0.55 a pound at Store B.
If a customer wants to buy 10 pounds of bananas from store A and store B,
The customer would spend 0.59 × 10 pounds of bananas = $5.9
buying from store A and
The customer would spend 0.55 × 10 pounds of bananas = $5.5
buying from store B.
The customer spends more for 10 pounds of bananas if he buys from shop A.
The customer saves 5.9 - 5.5 = $0.5
when he shops at store B
Answer:
Change = -(1/2) * 30 = -15 inches
Step-by-step explanation:
If the water level decreases by 1/2 inch each day, the change in the water level in one day is -1/2 inch.
So, after t days, the total change in the water level can be calculated as:
Total change = -(1/2) * t inches
So, after 30 summer days, the total change is:
Change = -(1/2) * 30 = -15 inches
So the water level of the pool after 30 summer days has decreased by 15 inches.
Answer:
<u>The correct answer is that a student have to score 1.41 standard deviations above the mean to be publicly recognized.</u>
Step-by-step explanation:
For answering the question, we don't know the score mean of the National Financial Capability Challenge Exam and neither the population or number of students who take the exam. The only information provided is that the public recognition in this normal distribution is only for students that scores in the top 8%. In other words for students above 92% of the population.
With this information, we can go to a Z Score Table and check that for being on the top 8% (above the 92% of any population), your result must be 1.405 standard deviations above the mean.
<u>Rounding the answer to 2 decimal places, it's 1.41 standard deviations above the mean.</u>