All categories

2 years ago

how do i slove 5/9v+w=z, for v

1 answer:

3 0

Okay, let's do this~

we want v isolated on one side so let's bring w over through subtraction

now we have 5/9v=z-w

now, to get rid of that fraction attached to v, we will multiply it's reciprocal on both sides.

*the reciprocal of 5/9 is 9/5

(5/9) x (9/5) cancel each other leaving v isolated to the left

the other side should look like this 9/5(z-w)

now we put both parts together to end up with:

v= 9/5(z-w)

there you go! :D

You might be interested in

If an exponential model was used to fit the data set below, which of the following would be the best prediction for the output o

satela [25.4K]

Answer:

The equation is found to be: $y = 50.6e^{0.16x}$

y(20) = 1241.34

Step-by-step explanation:

The given data is:

x: 3 7 11 14 17

y: 83 142 301 450 722

Now, we find sum summation values, relevant to the formula of exponential regression model, using calculator:

∑ ln y = 27.77305, ∑x ln y = 308.1494, ∑x = 52, ∑ x² = 664

and, n = no. of data points = 5

Now, we use formulae of exponential regression model to find out values of constant:

b = (n∑x lny - ∑x ∑ln y)/[n∑x² - (∑x)²]

b = [(5)(308.1494) - (52)(27.77305)]/[(5)(664) - (52)²]

b = 0.16

Now, for a;

a = (∑ln y - b∑x)/n

Therefore,

a = [(27.77305) - (0.16)(52)]/5

a = 3.9

For, α:

α = e^a = e^3.9

α = 50.6

So, the final equation of exponential regression model is given as:

$y = \alpha e^{bx}\\ y = 50.6e^{0.16x}$

Now, we find value of y for x = 20:

y(20) = (50.6) e^(0.16*20)

8 0

2 years ago

Which represents a quadratic function? f(x) = −8x3 − 16x2 − 4x f (x) = three-quarters x 2 + 2x − 5 f(x) = StartFraction 4 Over x

tatyana61 [14]

Answer:

$2.\ f(x) = \frac{3}{4}x^2 + 2x - 5$

Step-by-step explanation:

Given

$f(x) = -8x^3 - 16x^2 - 4x\\f(x) = \frac{3}{4}x^2 + 2x - 5\\f(x) = \frac{4}{x^2} - \frac{2}{x} + 1\\f(x) = 0x^2 - 9x + 7$

Required

Which of the above is a quadratic function

A quadratic function has the following form;

$ax^2 +bx + c = 0 \ where \ a\neq 0$

So, to get a quadratic function from the list of given options, we simply perform a comparative test of each function with the form of a quadratic function

$1.\ f(x) = -8x^3 - 16x^2 - 4x$

This is not a quadratic function because it follows the form $f(x) = ax^3 + bx^2 + c$ and this is different from $ax^2 +bx + c = 0 \ where \ a\neq 0$

$2.\ f(x) = \frac{3}{4}x^2 + 2x - 5$

This function has an exact match with $ax^2 +bx + c = 0 \ where \ a\neq 0$

By comparison; $a = \frac{3}{4}\ b = 2\ and\ c = -5$

$3.\ f(x) = \frac{4}{x^2} - \frac{2}{x} + 1$

This is not a quadratic function because it follows the form $f(x) = \frac{a}{x^2} + \frac{b}{x} + c$ and this is different from $ax^2 +bx + c = 0 \ where \ a\neq 0$