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kramer
1 year ago
15

The map needs to be reproduced at a different scale so that it has an area of 6 square inches and can fit in a brochure at what

scale should the map be reproduced so that it fits on the brochure
Mathematics
1 answer:
Ilia_Sergeevich [38]1 year ago
5 0

Answer:

4 inches

Step-by-step explanation:

The computation of the scale that should be required to reproduced that fitted on the brochure is

Given that

Length of rectangular park = 4 inches

And the Breadth of rectangular park = 6 inches

As we know that

Area of rectangular park = length × breadth

= 4×6

= 24 square inches

Now the scale that required to reproduced is

= 24 ÷ 6

= 4 inches

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Chris and Ben walked home from school. The distance Chris walked,in miles, is represented by point C on the number line. Ben wal
Xelga [282]

first you divide the amount of miles chris walked with 1/4 or .25 miles then you will get the answer

3 0
2 years ago
105,159 rounded to the nearest ten thousand
ivolga24 [154]

For this case we have the following number:

105,159

By definition we have:

thousand place: five-digit number greater than zero.

On the other hand we have as a rule:

When the previous number is greater than or equal to five, then the next number increases by one.

So we have to round off to the nearest ten thousand:

105,159 = 110,000

Answer:

105,159 rounded to the nearest ten thousand is:

105,159 = 110,000

6 0
2 years ago
Read 2 more answers
A company produces and sells 211,600 boxes of t-shirts each year. Each production run has a fixed cost of $400 and an additional
Illusion [34]

Answer:x=46

Step-by-step explanation:

Given

Company Produces and sells 211600 boxes of T-shirt each year

Fixed cost =$ 400

Additional cost = $ 3 per box

storage cost =$ 2

let x be the no of production run

therefore

Holding cost per year =holding\ cost\times average\ holding\ items=2\times \frac{211600}{2x}=\frac{211600}{x}

Yearly\ ordering\ cost=cost\ during\ each\ order\times number\ of\ order\ Placed\ per\ year

yearly ordering cost=400x+3\times \frac{211600}{x}

Total cost C(x)=\frac{211600}{x}+400x+3\times \frac{211600}{x}

differentiate C(x) w.r.t to x we get

\frac{\mathrm{d} C(x)}{\mathrm{d} x}=400-\frac{3\times 211600}{x^2}-\frac{1}{211600}

Put \frac{\mathrm{d} C(x)}{\mathrm{d} x}=0 to get max/min value

400-\frac{211600}{x^2}-\frac{3\times 211600}{x^2}=0

x^2=\frac{211600}{100}

x=\sqrt{2116}

x=46

therefore 46 runs must be performed

5 0
1 year ago
A ball is launched into the sky at 19.6 feet per second from a 58.8 meter tall building. The equation for the ball's height. h,
Crazy boy [7]
H represents the height of the ball at a given time, symbolised as t.
Thus, we just need to find when h = 0 so that we find when it hits the ground.

0 = -4.9t² + 19.6t + 58.8
0 = 4.9t² - 19.6t - 58.8
0 = 49t² - 196t - 588
0 = t² - 4t - 12
0 = (t - 6)(t + 2)

So, t = 6 or -2, but t ≠ -2, since time cannot be negative in this instance.

Hence, at 6 seconds, the ball will strike the ground.
3 0
1 year ago
A ball is thrown upward and outward from a height of 77 feet. the height of the​ ball, f(x), in​ feet, can be modeled by f left
Oksi-84 [34.3K]
From the given function modeling the height of the ball:
f(x)=-0.2x^2+1.4x+7
A] The maximum height of the ball will be given by:
At max height f'(x)=0
from f(x), 
f'(x)=-0.4x+1.4
solving for x we get:
-0.4x=-1.4
x=3.5ft
thus the maximum height would be:
f(3.5)=-0.2(3.5)^2+1.4(3.5)+7
f(3.5)=9.45 ft

b]
How far from where the ball was thrown did this occur:
from (a), we see that at maximum height f'(x)=0
f'(x)=-0.4x+1.4
solving for x we get:
-0.4x=-1.4
x=3.5ft
This implies that it occurred 3.5 ft from where the ball was thrown.


 c] How far does the ball travel horizontally?
f(x)=-0.2x^2+1.4x+7
evaluationg the expression when f(x)=0 we get:
0=-0.2x^2+1.4x+7
Using quadratic equation formula:
x=-3.37386 or x=10.3739
We leave out the negative and take the positive answer. Hence the answer 10.3739 ft horizontally.
6 0
2 years ago
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