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1 year ago

Georgie joins a gym. She pays $25 to sign up and then $15 each monthLabel the y-intercept, the slope, and your axes.

1 answer:

7 0

The first thing you should do for this case is to find the equation of the line that best suits the problem and then plot it.

Let X: number of months and: amount paid.

The equation of the line is
y = 15x + 25 y-intercept = 25

the slope = 15

Answer:

Georgie pays (y axis) $ 15 dollars (the spole) monthly (x-axis) in the gym with a $ 25 registration (y -intercept)

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In a recent questionnaire about food, a random sample of 970 adults were asked about whether they prefer eating fruits or vegeta

alukav5142 [94]

Answer:

$Z_{0.05}=1.645$

Step-by-step explanation:

Given :In a recent questionnaire about food, a random sample of 970 adults were asked about whether they prefer eating fruits or vegetables, and 458 reported that they preferred eating vegetables.

To Find :What value of z should be used to calculate a confidence interval with a 95 % confidence level?

Solution:

Confidence level = 95 % i.e.0.95

So, significance level = 5% i.e. 0.05

So, the value of z corresponding to significance level 0.05 should be used to calculate a confidence interval with a 95 % confidence level

So, $Z_{0.05}=1.645$

Hence z should be 1.645 to calculate a confidence interval with a 95 % confidence level.

4 0

1 year ago

What type of polygon would a slice of a hexahedron at a vertex create? Explain. What type of polygon would a slice of an icosahe

harina [27]

Answer:

hexahedron: triangle or quadrilateral or pentagon
icosahedron: quadrilateral or pentagon

Step-by-step explanation:

Hexahedron

A hexahedron has 6 faces. A regular hexahedron is a cube. 3 square faces meet at each vertex.

If the hexahedron is not regular, depending on how those faces are arranged, a slice near a vertex may intersect 3, 4, or 5 faces. The first attachment shows 3- and 4-edges meeting at a vertex. If those two vertices were merged, then there would be 5 edges meeting at the vertex of the resulting pentagonal pyramid.

A slice near a vertex may create a triangle, quadrilateral, or pentagon.

Icosahedron

An icosahedron has 20 faces. The faces of a regular icosahedron are all equilateral triangles. 5 triangles meet at each vertex.

If the icosahedron is not regular, depending on how the faces are arranged, a slice near the vertex may intersect from 3 to 19 faces.

A slice near a vertex may create a polygon of 3 to 19 sides..

3 0

2 years ago

If a(x) = 3x + 1 and b (x) = StartRoot x minus 4 EndRoot, what is the domain of (b circle a) (x)?

kiruha [24]

Answer:

$[1,\infty)$

Step-by-step explanation:

$b(x)=\sqrt{x-4}$

$a(x)=3x+1$

Since we want to know the domain of $(b \circ a)(x)$ , let's first consider the domain of the inside function, that is, that of $a(x)=3x+1$ . Every polynomial function has domain all real numbers.

So we can plug anything for function $a$ and get a number back.

Now the other function is going to be worrisome because it has a square root. You cannot take square root of negative numbers if you are only considering real numbers which that is the case with most texts.

Let's find $(b \circ a)(x)$ and simplify now.

$(b \circ a)(x)$

$b(a(x))$

$b(3x+1)$

$\sqrt{(3x+1)-4}$

$\sqrt{3x+1-4}$

$\sqrt{3x-3}$

Now again we can only square root positive or zero numbers so we want $3x-3 \ge 0$ .

Let's solve this to find the domain of $(b \circ a)(x)$ .

$3x-3 \ge 0$

Add 3 on both sides:

$3x \ge 3$

Divide both sides by 3:

$x \ge 1$

So we want $x$ to be a number greater than or equal to 1.

The option that says this is $[1,\infty)$

-------------------------------

Give an example why option A fails:

A number in the given set is -2.

$a(x)=3x+1$

$b(x)=\sqrt{x-4}$

So $a(-2)=3(-2)+1=-6+1=-5$ and $b(-5)=\sqrt{-5-4}=\sqrt{-9} \text{ which is not real}$ .

Give an example why option B fails:

A number in the given set is 0.

$a(x)=3x+1$

$b(x)=\sqrt{x-4}$

So $a(0)=3(0)+1=0+1=1$ and $b(1)=\sqrt{1-4}=\sqrt{-3} \text{ which is not real}$ .

Give an example why option D fails:

While all the numbers in set D work, there are more numbers outside that range of numbers that also work.

A number not in the given set that works is 3.

$a(x)=3x+1$

$b(x)=\sqrt{x-4}$

So $a(3)=3(3)+1=9+1=10$ and $b(1)=\sqrt{10-4}=\sqrt{6} \text{ which is real}$ .

4 0

2 years ago

Read 2 more answers

On babylonian tablet ybc 4652, a problem is given that translates to this equation: x (x/7) (1/11) (x (x/7)) = 60 what is the so

Yanka [14]

Thanks for posting your question here. The answer to the above problem is x = 48.125. Below is the solution:

x+x/7+1/11(x+x/7)=60
x = x/1 = x • 7/7
x • 7 + x/ 7 = 8x/7 - 60 = 0
x + x/7 + 1/11 • 8x/7 - 60 = 0
8x • 11 + 8x/ 77 = 96x/ 77
96x - 4620 = 12 • (8x-385)
8x - 385 = 0
x = 48.125

5 0

2 years ago

Read 2 more answers

Is AB parallel to Bo? Explain.

Svetradugi [14.3K]

Answer:

AB parallel to CD because both lines have a slope of

of 4/3

Step-by-step explanation:

The question is not complete, there is no graph.

A graph for the question is attached below.

From the image attached below, line 1 passes through points A = (-3, -3) and point B = (0, 1) while line 2 passes through point C = (0, -5) and point D = (3, -1).

Two parallel are said to be parallel if the have the same slope. The slope of a line passing through points:

$(x_1,y_1)\ asnd\ (x_2,y_2).\ The\ slope \ is\ given\ as:\\\\Slope(m)=\frac{y_2-y_1}{x_2-x_1}$

Line 1 passes through points A = (-3, -3) and point B = (0, 1), the slope of line 1 is:

$Slope(m)=\frac{y_2-y_1}{x_2-x_1}=\frac{1-(-3)}{0-(-3)}=\frac{1+3}{0+3}=\frac{4}{3}$

Line 2 passes through point C = (0, -5) and point D = (3, -1). the slope of line 2 is:

$Slope(m)=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-5)}{3-0}=\frac{-1+5}{3}=\frac{4}{3}$

Therefore AB parallel to CD because both lines have a slope of

of 4/3

7 0

1 year ago