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marshall27 [118]
2 years ago
12

Malik randomly picked two numbers from 1 to 9 (Includin 1 and 9). the same number could be picked more than once. The first of t

he two numbers hr picks is odd and less than 5. What is the probability that the sum ofbthe number malik picks is less than 5, given that the first number is odd and lessbthan 5
Mathematics
1 answer:
Tju [1.3M]2 years ago
8 0

Answer:

2/9 = 0.22

Step-by-step explanation:

There are two ways to pick the first number odd and less than 5:  1 and 3.

With each of these, the second number drawn can be 1, 2, 3, 4, 5, 6, 7, 8 or 9.

This makes 18 total possibilities.

Out of these, the only ways to have a sum less than 5 are 1 and 1, 1  and 2, 1 and 3, and 3 and 1.  This is 4 ways out of 18:

4/18 = 2/9 = 0.22

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Which statements are true about circle Q? Select three options. The ratio of the measure of central angle PQR to the measure of
kkurt [141]

Answer:

<h3>- The ratio of the measure of central angle PQR to the measure of the entire circle is One-eighth. </h3><h3>- The area of the shaded sector depends on the length of the radius. </h3><h3>- The area of the shaded sector depends on the area of the circle</h3>

Step-by-step explanation:

Given central angle PQR = 45°

Total angle in a circle = 360°

Ratio of the measure of central angle PQR to the measure of the entire circle is \frac{45}{360} = \frac{1}{8}. This shows ratio that <u>the measure of central angle PQR to the measure of the entire circle is one-eighth</u>.

Area of a sector = \frac{\theta}{360}*\pi r^{2}

\theta = central angle (in degree) = 45°

r = radius of the circle = 6

Area of the sector

= \frac{45}{360}*\pi (6)^{2}\\ = \frac{1}{8}*36 \pi\\  = 4.5\pi units^{2}

<u>The ratio of the shaded sector is 4.5πunits² not 4units²</u>

From the formula, it can be seen that the ratio of the central angle to that of the circle is multiplied by area of the circle, this shows <u>that area of the shaded sector depends on the length of the radius and the area of the circle.</u>

Since Area of the circle = πr²

Area of the circle = 36πunits²

The ratio of the area of the shaded sector to the area of the circle = \frac{4.5\pi }{36 \pi } = \frac{1}{8}

For length of an arc

= \frac{45}{360}*2\pi r\\= \frac{45}{360}*2\pi (6)\\= \frac{45}{360}*12 \pi \\= \frac{12\pi }{8} \\= \frac{3\pi }{2} units

ratio of the length of the arc to the area of the circle = \frac{\frac{3\pi}{2} }{36\pi} = \frac{3}{72} =\frac{1}{24}

It is therefore seen that the ratio of the area of the shaded sector to the area of the circle IS NOT equal to the ratio of the length of the arc to the area of the circle

5 0
2 years ago
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PLEASE HELP!! Which steps can be used to solve 6/7x+1/2=7/8 for x? Check all that apply. A. Divide both sides of the equation by
Anon25 [30]

Answer:

B. first step

6/7x=7/8-1/2

c. second step

6/7x=7/8-4/8=3/8

d. and e are the same

x=3/8x7/6

Step-by-step explanation:

5 0
2 years ago
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A kite is made up of two isosceles triangles, KIT and KET, with the lengths shown. The top triangle of the kite, ΔKIT, is made f
Annette [7]
The correct answer would be 48 square inches
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Convert decimal +49 and +29 to binary, using the signed‐2’s‐complement representation and enough digits to accommodate the numbe
Serhud [2]

To solve this problem, let us first find for the binary equivalents of the numbers. They are:

Decimal --> Binary

+ 29 --> 00011101

+ 49 --> 00110001

- 29 --> 11100011

- 49 --> 11001111

Now we apply the normal binary arithmetic to these converted numbers:

(+ 29) + (- 49) ---> 00011101 + 11001111 = 11101100 ---> - 20 (TRUE)

(- 29) + (+ 49) ---> 11100011 + 00110001 = 00010100 ---> + 20 (TRUE)

(- 29) + (- 49) ---> 11100011 + 11001111 = 10110010 ---> - 78 (TRUE)

5 0
2 years ago
A formula calls for 0.6 mL of a coloring solution. Using a 10-mL graduate calibrated from 2 to 10 mL in 1-mL units, how could yo
MrMuchimi

Answer:

let us add 2.4 mL of water in 0.6 ml of coloring solution

total volume of solution = 2.4 + 0.6 = 3 mL

therefore,

0.6 mL of coloring solution now includes = 2.4ml of water

or

1 mL of coloring solution includes = 4mL of water

Hence

measure 3 mL of coloring solution with water that is formed

therefore, this 3 mL will contain 0.6 mL of coloring solution

Step-by-step explanation:

Given:

formula calls for 0.6 mL of a coloring solution

10-mL graduate calibrated from 2 to 10 mL in 1-mL units

Now,

We want to use an aliquot technique to measure 0.6 ml of coloring solution.

Because the calibrated graduate is used to measure 2ml to 10ml with 1ml as unit measure

let us add 2.4 mL of water in 0.6 ml of coloring solution

total volume of solution = 2.4 + 0.6 = 3 mL

therefore,

0.6 mL of coloring solution now includes = 2.4ml of water

or

1 mL of coloring solution includes = 4mL of water

Hence

measure 3 mL of coloring solution with water that is formed

therefore, this 3 mL will contain 0.6 mL of coloring solution

3 0
2 years ago
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