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2 years ago

HELPP ASAP NEEDED MATH

Mathematics

2 answers:

trapecia [35]2 years ago

6 0

Answer:

992

Step-by-step explanation:

Divide 1000 by 26.

The answer is 38 and some left over. We don't care what the leftover is because it is nearly 0.5 and that means 13 people were left over.

Take the integer value (38) and multiply it by 26. You get 988.

You want there to be 4 left over. 4 + 988 = 992. That's one way of doing the problem.

Umnica [9.8K]2 years ago

3 0

Answer: 940 people is the maximum

==========================================

Explanation:

n = 1 means 20n = 20*1 = 20 members total, which is 4 short of making a row of 26 (so the remainder is 20)

n = 2 means 20n = 20*2 = 40 members. 40/26 = 1 remainder 14. We could make one full row with 14 members left over.

20n < 1000 solves to n < 50 after dividing both sides by 20. This means n is smaller than 50. It has to be larger than 0 or else 20n would be 0 or negative. We can write 0 < n < 50 to specify the range for n.

Since n < 50, this means the largest n can get is n = 49.

--------------------

If n = 49, then 20n = 20*49 = 980

980/26 = 37 remainder 18, which isn't the remainder we want (of 4).

If n = 48, then 20n = 20*48 = 960

960/26 = 36 remainder 24, again not the remainder we want

If n = 47, then 20n = 20*47 = 940

940/26 = 36 remainder 4

If we have 940 members, then we can form 36 rows (26 in each row). So 26*36 = 936 people so far. Then we have 940-936 = 4 people left over.

There are other solutions as well such as n = 34, n = 21, and n = 8. Though n = 47 is the largest n possible to fit all the conditions required.

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Can anyone please help me with this question? : A target consists of two concentric circles. The larger circle has diameter 1m.

11111nata11111 [884]

We know that
if <span>the probability of hitting the blue circle is the same as the probability of hitting the green region
then
the area of the blue circle is equal to the area of the green region

Let
x----> diameter of the blue circle

area of the blue circle=pi*(x/2)</span>²----> (pi/4)*x² m²-----> equation 1

area of the green region=area of the larger circle-area of the blue circle
area of the green region=pi*(1/2)²-(pi/4)*x²
=(pi/4)-(pi/4)*x² m²----> equation 2

equate equation 1 and equation 2
(pi/4)*x²=(pi/4)-(pi/4)*x² -----> divide by (pi/4)---> x²=1-x²
2x²=1-----> x²=1/2----> x=1/√2-----> x=√2/2 m

the diameter of the blue circle is √2/2 m

5 0

2 years ago

Tonyas dog walking service charges a flat rate of $20 per month, plus $3 per mile that each dog is walked. beth does not charge

andreev551 [17]

Answer:

Step-by-step explanation:

given that tonya charges 20$ monthly fee and 3$ per mile of her dog-walking service.

and beth does not charge any monthly fee but charges 5$ per mile of the dog walked in.

let x be the number of miles dog has walked in a month.

the amount tonya will charge on x miles = fixed monthly fee + number of miles * charge per mile = 20+3x

and the amount beth will charge on x miles = 0+ 5*x = 5x.

we are asked to find the x-value for which beth chargeable amount = tonya chargeable amount

that is 5x = 20+3x

5x-2x = 20

2x=20

x= $\frac{20}{2} = 10$

hence number of miles for which tonya and beth will charge the same amount is 10.

7 0

2 years ago

One hundred teachers attended a seminar on mathematical problem solving. The attitudes of representative sample of 12 of the tea

andrew11 [14]

Answer:

a) 1.92

b) 3.25

c) 1.5

d) -5.23

Step-by-step explanation:

We are given the following in the question:

4, 7, -1, 1, 0, 5, -2, 2, -1, 6, 5, -3

a) mean of score change

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{23}{12} = 1.92$

b) standard deviation for this population

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

Sum of squares of differences = 126.92

$\sigma = \sqrt{\frac{126.92}{12}} = 3.25$

c) median change score

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$