The 300th customer would be the first to recieve both. They would have given away 5 of the 20$ gift cards and 12 of the 10$ ones for a total of 17 gift cards.
Answer:
Option B is correct.
Use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.
Step-by-step Explanation:
The clear, complete table For this question is presented in the attached image to this solution.
It should be noted that For this question, the running coach wants to test if participating in weekly running clubs significantly improves the time to run a mile.
In the data setup, the mean time to run a mile in January for those that participate in weekly running clubs and those that do not was provided.
The mean time to run a mile in June too is provided for those that participate in weekly running clubs and those that do not.
Then the difference in the mean time to run a mile in January and June for the two classes (those that participate in weekly running clubs and those that do not) is also provided.
Since, the aim of the running coach is to test if participating in weekly running clubs significantly improves the time to run a mile, so, it is logical that it is the improvements in running times for the two groups that should be compared.
Hence, we should use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.
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The answer is 160, multiply 12 by 4 to get 48 cats. 40 multiplied by 4 = 160.
If that makes since.
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Provide the approximated measurement to associate the volume of water.
Answer:
The quadratic equation is x^2-2x-4
Step-by-step explanation:
We want to know the equation that has the solution below;
x = 1 ± √5
This means x = 1 + √5 or 1 - √5
The equation would thus be;
(x-1-√5)(x-1+ √5)
= x(x-1+ √5)-1(x-1+ √5)-√5(x-1+ √5)
Opening the brackets we have ;
x^2-x+ √5x-x + 1 -√5-√5x+ √5-5
collecting like terms we have;
x^2-2x+1-5
= x^2-2x-4