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schepotkina [342]
2 years ago
12

desiree has 100 pink 80 blue and 120 purple beads. she puts all of the beads into jars equally. each jar has one type of bead. h

ow many beads can she put in one jar
Mathematics
1 answer:
astra-53 [7]2 years ago
8 0
At most, 20. 20 is the greatest common factor of all numbers.
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The price of apples went from $0.30 per lb to $0.90 per lb in three years. Find the rate of change of the price of apples.
Brut [27]
90c-30c=60cent change

60cents/3years=20cents/year

It changed 20cents a year
3 0
2 years ago
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Find the simplified product b-5/2b x b^2+3b/b-5
White raven [17]

Answer:

The product \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

Step-by-step explanation:

Given expression \frac{b-5}{2b} and \frac{b^2+3b}{b-5}

We have to find the product of  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

   

Consider the given expression  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

Multiply fractions, we have,

\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}

=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}

Cancel common factor ( b - 5 )

we have, =\frac{b^2+3b}{2b}

Apply exponent rule,

\:a^{b+c}=a^ba^c

b^2=bb

=bb+3b=b(b+3)

=\frac{b\left(b+3\right)}{2b}

Cancel common factor b , we have,

=\frac{b+3}{2}

Thus, the product  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

8 0
2 years ago
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Janis was offered two different jobs when she graduated from college. She made the graph and table to show how much she would ea
REY [17]

Answer: A)

Step-by-step explanation:

<em>aint no body got time for dat!!</em>

Hope this helps!

8 0
2 years ago
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In december 1994 a man in ohio decided to deposit all of the 8 million pennies he had been saving for nearly 65 years. (his depo
STatiana [176]
8,000,000 pennies equals $80,000. 1/.05=20
20 x $80,000=$1,600,000 more that the bank was able to lend
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6 0
2 years ago
A tunnel is in the shape of a parabola. The maximum height is 16 m and it is 16 m wide at the base, as shown below.
NeX [460]
Vertex at the origin and opening down → y=ax^2
Width: w=16
x=w/2→x=16/2→x=8
x=8, y=-16→y=ax^2→-16=a(8)^2→-16=a(64)→-16/64=a(64)/64→-1/4=a→a=-1/4

y=ax^2→y=-(1/4)x^2

7 m from the edge of the tunnel → x=w/2-7=8 m-7 m→x=1 m
x=1→y=-(1/4)x^2=-(1/4)(1)^2=-(1/4)(1)→y=-1/4

Vertical clearance: 16-1/4=16-0.25→Vertical clearance=15.75 m

Please, see the attached file.

Answer: Third option 15.75 m

3 0
2 years ago
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