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Zina [86]
2 years ago
12

Andy,Taylor and Ben share their team payment in a ratio of 1:3:4. What % dies Andy receive

Mathematics
2 answers:
jarptica [38.1K]2 years ago
8 0

Answer: 12.5%

Step-by-step explanation: Ratio describes the relative magnitudes between quantities. Their payment is given in the ratio of 1:3:4. Andy = 1, Taylor = 3, and Ben = 4

To figure out the ratio Andy receives, we first add the ratios together to get the sum of ratios.

Therefore, 1 + 3 + 4 = 8

Andy receives 1 out of 8 = ⅛

Representing fractions as percentages, we simply multiply by 100/1.

⅛ x (100/1) = 100/8 = 12.5%

Therefore, Andy receives 12.5% as his share of their team payment.

matrenka [14]2 years ago
7 0
Andy receives 1 share out of 8 total.

\frac{1}{8} *100=12.5 \text{ percent}
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Answer:

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Explanation:

we have been given with the quadratic equation x^2-8x-9

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from given quadratic equation a=1,b= -8,c= -9

substituting these values in the formula for discriminant D=b^{2}-4ac

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Now, to find the value of x

Formula is x=\frac{-b\pm\sqrt{D}}{2a}

Now, substituting the values we will get

x=\frac{-(-8)\pm\sqrt{100}} {2}= \frac{8\pm10}{2}=9,-1

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Step-by-step explanation:

After <em>t </em>years, the number of goats is given by

N = N_0e^{bt}

where N_0 is the initial number of goats and <em>b</em> is the per capita growth rate.

From the question,

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Answer:

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b) \hat p=\frac{973}{1714}=0.568 represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

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Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

Description in words of the parameter p

p represent the real population proportion of people who showed partial or complete resistance to the antibiotic

\hat p represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

n=1714 is the sample size required

z_{\alpha/2} represent the critical value for the margin of error

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Part b

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

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Part c

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\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

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And the 95% confidence interval would be given (0.545;0.591).

We are confident that about 54.5% to 59.1% of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic.  

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