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andreyandreev [35.5K]
2 years ago
13

A daycare made $40 during their first month in business. They doubled the amount of money they earned each month. What is the to

tal amount of money they earned after a year? $4096 $81,900 $163,800 $81,920
please give answer and way you found it im trying to learn but the way my teacher explained it doesn't make sense
Mathematics
2 answers:
AfilCa [17]2 years ago
6 0

Answer:

$81,920

Step-by-step explanation:

money made by january: $40

double that

money made by february: $80

double that

money made by march: $160

double that

money made by april: $320

double that

money made by may: $640

double that

money made by june: $1,280

double that

money made by july: $2,560

double that

money made by august: $5,120

double that

money made by september: $10,240

double that

money made by october: $20,480

double that

money made by november: $40,960

double that

money made by december: $81,920

the total money they made by the end of the year (december) was $81,920

DochEvi [55]2 years ago
5 0

Answer:

$163,800

Step-by-step explanation:

40, 80, 160, 320...

It's a geometric progression

With first term = 40

Common ratio = 80/40 = 2

After 1 year is 12 months

Find S12.

S12 = 40(2¹² - 1)/(2 -1)

= 163800

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Rename the number 7 so you can find the difference of 7 - 3 5/12
stiks02 [169]
7-3 \frac{5}{12}=6 \frac{12}{12}-3\frac{5}{12}=3 \frac{7}{12}
6 0
2 years ago
se the function to show that fx(0, 0) and fy(0, 0) both exist, but that f is not differentiable at (0, 0). f(x, y) = 9x2y x4 + y
alexandr1967 [171]

Answer:

It is proved that f_x, f_y exixts at (0,0) but not differentiable there.

Step-by-step explanation:

Given function is,

f(x,y)=\frac{9x^2y}{x^4+y^2}; (x,y)\neq (0,0)

  • To show exixtance of f_x(0,0), f_y(0,0) we take,

f_x(0,0)=\lim_{h\to 0}\frac{f(h+0,k+0)-f(0,0)}{h}=\lim_{h\to 0}\frac{\frac{9h^2k}{h^4+k^2}-0}{h}\\\therefore f_x(0,0)=\lim_{h\to 0}\frac{9hk}{h^4+k^2}=\lim_{h\to 0}\frac{9k}{h^3+\frac{k^2}{h}}=0    exists.

And,

f_y(0,0)=\lim_{k\to 0}\frac{f(h,k)-f(0,0)}{k}=\lim_{k\to 0}\frac{9h^2k}{k(h^4+k^2)}=\lim_{k\to 0}\frac{9h^2}{h^4+k^2}=\frac{9}{h^2}   exists.

  • To show f(x,y) is not differentiable at the origin cheaking continuity at origin be such that,

\lim_{(x,y)\to (0,0)}\frac{9x^2y}{x^4+y^2}=\lim_{x\to 0\\ y=mx^2}\frac{9x^2y}{x^4+y^2}=\frac{9x^2\times m x^2}{x^4+m^2x^4}=\frac{9m}{1+m^2}  where m is a variable.

which depends on various values of m, therefore limit does not exists. So f(x,y) is not continuous at (0,0). Hence it is not differentiable at (0,0).

4 0
2 years ago
Write the converse of the following statement and determine its truth value:
icang [17]

Answer:

The converse is:

if the ratio of lefties to righties is 1 : 8, then for every 3 left handed people, there are 24 right handed people.

The truth value is:

True

Step-by-step explanation:

The statement can be split into:

p -> If a class has 3 left-handed people and 24 right-handed people,

q -> the ratio of lefties to righties is 1:8

The converse of a conditional statement is:

if q then p

So, we have the converse to be;

if the ratio of lefties to righties is 1 : 8, then for every 3 left handed people, there are 24 right handed people.

The truth value.

For p, we have.

Ratio = 3 : 24

This can be simplified to.

Ratio = 1 : 8

For q, we have:

Ratio = 1 : 8

<em>Since both are true, then the truth value is true</em>

4 0
2 years ago
Farmer John walks his pet pig around his barn every day. The barn is 25
kkurt [141]

Answer:

900m

Step-by-step explanation:

A=wl

W=25

L=12

A=25 x 12

A= 300

300 meters x 3 laps = 900 meters walked

4 0
2 years ago
Reyna has 5 coins worth 10 cents each and 4 coins
Zolol [24]

Answer:

The Probability found is:

P =  \frac{13}{18}

Step-by-step explanation:

Let x be the 10 cents coin.

Let y be the 25 cents coin.

We have to find all the possible outcomes

1) First coin = 10 cents, Second coin = 10 cents , so

(x,x) = 20

2) First coin = 10 cents, Second coin = 25 cents , so

(x,y) = 35

3) First coin = 25 cents, Second coin = 10 cents , so

(y,x) = 35

4) First coin = 25 cents, Second coin = 25 cents , so

(y,y) = 50

Find the probability of each outcome:

P(x,x) =  \frac{5}{9}\cdot\frac{4}{8}=\frac{20}{72}

P(x,y) =  \frac{5}{9}\cdot\frac{4}{8}=\frac{20}{72}

P(y,x) =  \frac{5}{9}\cdot\frac{4}{8}=\frac{20}{72}

P(y,y) = \frac{4}{9}\cdot\frac{3}{8}=\frac{12}{72}

Add all the probabilities where sum is at least 35 i.e P(x,y) , P(y,x) , P(y,y)

P(x,y) + P(y,x) + P(y,y) = \frac{20}{72}+\frac{20}{72}+\frac{12}{72} = \frac{52}{72}=\frac{13}{18}\\

6 0
2 years ago
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