"The difference between five-halves of a number<br> and 17 is 48."

A production line operates with a mean filling weight of 16 ounces per container. Overfilling or underfilling presents a serious

Dominik [7]

Answer:

Part1) $z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191$

$p_v =2*P(Z>2.191)=0.0284$

Readjustment is needed

Part 2) $z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232$

$z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232$

$p_v =2*P(Z$

No readjustment is needed

Step-by-step explanation:

Data given and notation

Part 1

$\bar X=16.32$ represent the sample mean

$\sigma=0.8$ represent the population standard deviation

$n=30$ sample size

$\mu_o =16$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a two tailed test.

What are H0 and Ha for this study?

Null hypothesis: $\mu =16$

Alternative hypothesis : $\mu \neq 16$

Compute the test statistic

The statistic for this case is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191$

Give the appropriate conclusion for the test

Since is a two tailed test the p value would be:

$p_v =2*P(Z>2.191)=0.0284$

Using the value of $\alpha =0.05$ we see that $pv$ and we have enough evidence to reject the null hypothesis.

Readjustment is needed

The rejection zone is given by:

$(-\infty ;-1.96) , (1.96;\infty)$

Part 2

$\bar X=15.82$ represent the sample mean

We can replace in formula (1) the info given like this:

$z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232$

Give the appropriate conclusion for the test

Since is a two tailed test the p value would be:

$p_v =2*P(Z$

Using the value of $\alpha =0.05$ we see that $pv>\alpha$ and we have enough evidence to FAIL to reject the null hypothesis.

No readjustment is needed

The rejection zone is given by:

$(-\infty ;-1.96) , (1.96;\infty)$

What action would you recommend ?

Review the procedure.

Do you reach the same conclusion ?

No we got different conclusions

5 0

2 years ago

Lois says any addition equation where the addends are all the same can be written as a multiplication equation. Is Lois correct

USPshnik [31]

Lois is correct. This is because multiplication is repeated addition. It means that when your addends are just the same number but added several times, the sum is just equivalent to the product of that number times the number of times it was added. For example, 4+4+4 = 4×3 = 12.

6 0

2 years ago

Jolyn, a golfer, claims that her drive distance is not equal to 222 meters, on average. Several of her friends do not believe he

Troyanec [42]

Answer:

0.29

Step-by-step explanation:

z-score is given by the formula:

z=(μ-M)/σ where

μ is the hypothesis drive distance, which is 222
M is the mean sample drive distance
σ is the standard deviation of the sample drive distance

Therefore

z=(222-218)/14≈0.29

3 0

2 years ago

If the 180 food calories found in a granola bar come entirely from p grams of protein, f grams of fat, and c grams of carbohydra

Mice21 [21]

f = 180 - p - c

to find the amount of fat subtract the protein and carbs from the original 180 calories

3 0

2 years ago

Read 2 more answers

3.5 hours:$10 1/2 hour:$1.25. What is the unit rate in dollars per hour for each company?

Rasek [7]

One company wants $10 per 3.5 hours, so they want 10 / 3.5 ≈ 2,86 dollars per hour (after rounding to the closest hundreths).

Second company wants $1.25 per half an hour, so they want 2 * 1,25 = 2,50 dollars per hour.

The unit rate is 2,86:2,50

7 0

2 years ago

"The difference between five-halves of a number and 17 is 48."