A sports statistician was interested in the relationship between game attendance (in thousands) and the number of
1 answer:
Answer:
The predicted number of wins for a team that has an attendance of 2,100 is 25.49.
Step-by-step explanation:
The regression equation for the relationship between game attendance (in thousands) and the number of wins for baseball teams is as follows:
Here,
<em>y</em> = number of wins
<em>x</em> = attendance (in thousands)
Compute the number of wins for a team that has an attendance of 2,100 as follows:
Thus, the predicted number of wins for a team that has an attendance of 2,100 is 25.49.
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Answer:
<h3>The correct expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction</h3>Step-by-step explanation:
Given the expression for x ≠ 0, y ≠ 0 to get the equivalent expression we will have to simplify the given expression.
The correct expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction
Answer:
(a) 0.7967
(b) 0.6826
(c) 0.3707
(d) 0.9525
(e) 0.1587
Step-by-step explanation:
The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and variance <em>σ</em>² = 36.
(a)
Compute the value of P (X > 5) as follows:
Thus, the value of P (X > 5) is 0.7967.
(b)
Compute the value of P (4 < X < 16) as follows:
Thus, the value of P (4 < X < 16) is 0.6826.
(c)
Compute the value of P (X < 8) as follows:
Thus, the value of P (X < 8) is 0.3707.
(d)
Compute the value of P (X < 20) as follows:
Thus, the value of P (X < 20) is 0.9525.
(e)
Compute the value of P (X > 16) as follows:
Thus, the value of P (X > 16) is 0.1587.
**Use a <em>z</em>-table for the probabilities.