answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andre45 [30]
2 years ago
13

Find the GCF of 44j5k4 and 121j2k6.

Mathematics
2 answers:
garri49 [273]2 years ago
7 0
Its 11j2k4 because well i just know trust me my dude
BartSMP [9]2 years ago
3 0

Answer:

D. 11j^2k^4

Step-by-step explanation:

We are asked to find the GCF of 44j^5k^4\text{ and }121j^2k^6.

Since we know that GCF of two numbers is the greatest number that is a factor of both of them.

First of all we will GCF of 44 and 121.

Factors of 44 are: 1, 2, 4, 11, 22, 44.

Factors of 121 are: 1, 11, 11, 121.

We can see that greatest common factor of 44 and 121 is 11.

Now let us find GCF of j^5\text{ and }j^2.

Factors of j^5 are: j*j*j*j*j

Factors of j^2 are: j*j

We can see that greatest common factor of j^5\text{ and }j^2 is j*j=j^2.

Now let us find GCF of k^4\text{ and }k^6.

Factors of k^4 are: k*k*k*k    

Factors of k^6 are:k*k*k*k*k*k

We can see that greatest common factor of  k^4\text{ and }k^6 is k*k*k*k=k^4.

Upon combining our all GCFs we will get,

11j^2k^4  

Therefore, GCF of 44j^5k^4\text{ and }121j^2k^6 is 11j^2k^4 and option D is the correct choice.

You might be interested in
Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.
Thepotemich [5.8K]

Answer:

this is geometry?

Step-by-step explanation:

5 0
2 years ago
URGENT!!! Connor earns $24 working every 1.5 hours. Complete the table using equivalent ratios.
tamaranim1 [39]
First find the rate, so dollars/1 hour

To do this, divide both sides by 1.5 so u get the Pay of one hour because 1.5/1.5 is one and the result is 16/1 hour, now multiply 16 by the hour so 16(8) then 16(12) and so on, you can do it well! I don’t have a calculator lol
8 0
2 years ago
Read 2 more answers
The slope of diagonal OA is ? and its equation is ?
Nimfa-mama [501]

Answer:

Slope = \frac{4}{3}

Equation of the line → y=\frac{4}{3}x

Step-by-step explanation:

Let the equation of diagonal OA is,

y = mx + b

Here, m = Slope of the line OA

b = y-intercept

Slope of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

m = \frac{y_2-y_1}{x_2-x_1}

Therefore, slope of the line passing through O(0, 0) and A(3, 4) will be,

m = \frac{4-0}{3-0}

m = \frac{4}{3}

Since, line OA is passing through the origin, y-intercept will be 0.

Therefore, equation of OA will be,

y=\frac{4}{3}x

3 0
2 years ago
Please enter the missing number: 2, 9, 20, 37, 64, 107, ?
k0ka [10]
174 is the missing number
4 0
2 years ago
An experiment was performed to compare the abrasive wear of two different laminated materials. Twelve pieces of material 1 were
vladimir1956 [14]

Answer:

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

There is  significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units

Step-by-step explanation:

<u>Step:-(1)</u>

Given data the samples of material 1 gave an average (coded) wear of 85 units with a sample standard deviation of 4

Mean of the first sample x₁⁻ =85

standard deviation of the first sample S₁ = 4

Given data the samples of material 2 gave an average of 81 and a sample standard deviation of 5.

Mean of the first sample x₂⁻ =81

standard deviation of the first sample S₂ = 5

<u>Step :-2</u>

<u>Null hypothesis: H₀:</u> there is no significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

<u>Alternative hypothesis :H₁: </u>there is  significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Assume the populations to be approximately normal with equal variances.σ₁² =σ₂²

The test statistic

                     Z= \frac{x_{1} -x_{2} }{\sqrt{\frac{S^2_{1} }{n_{1} } +\frac{S^2_{2} }{n_{2} }  } }

Given  n₁=n₂=60.

                    Z= \frac{85-81 }{\sqrt{\frac{(4)^2 }{60 } +\frac{5^2 }{60}  } }

On calculation, we get

                   Z =   \frac{4}{\sqrt{0.6833} }

                   z = 4.8389

The tabulated value Z =1.96 at 0.05 level of significance.

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

Conclusion:-

there is  significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units.

3 0
2 years ago
Other questions:
  • A new building is 25 meters tall. how many decimeters tall is the building?
    14·2 answers
  • Michael made 4 dozen chocolate chip cookies he is bringing 75% of them to school for a party how many cookies does he bring to c
    8·1 answer
  • Jason has a piece of wire that is 62.4 inches long.He cuts the wire into 3 equal pieces.Estimate the length of 1 piece of wire.
    9·1 answer
  • The masses of the oranges on sale at a farm stand are normally distributed with a mean of 239 grams and a standard deviation of
    11·1 answer
  • Which size bottle of ketchup is the best deal with the lowest unit price? Prices for Different Sizes of Bottles of Ketchup Size
    12·2 answers
  • Simplify the following expression 3^0
    5·1 answer
  • Two wires with lengths of 448 cm and 616 cm are to be cut into pieces of all the same length without a remainder. Find the great
    15·1 answer
  • Ln triangle PQR, angle P-Q=20 and angle Q-R=50, find the value of angle R​
    9·2 answers
  • A moderately active 140 pound person will use 2100 calories per day to maintain that body weight, how many calories per day are
    7·1 answer
  • Help marking Brainly!!!
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!