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Andre45 [30]
2 years ago
13

Find the GCF of 44j5k4 and 121j2k6.

Mathematics
2 answers:
garri49 [273]2 years ago
7 0
Its 11j2k4 because well i just know trust me my dude
BartSMP [9]2 years ago
3 0

Answer:

D. 11j^2k^4

Step-by-step explanation:

We are asked to find the GCF of 44j^5k^4\text{ and }121j^2k^6.

Since we know that GCF of two numbers is the greatest number that is a factor of both of them.

First of all we will GCF of 44 and 121.

Factors of 44 are: 1, 2, 4, 11, 22, 44.

Factors of 121 are: 1, 11, 11, 121.

We can see that greatest common factor of 44 and 121 is 11.

Now let us find GCF of j^5\text{ and }j^2.

Factors of j^5 are: j*j*j*j*j

Factors of j^2 are: j*j

We can see that greatest common factor of j^5\text{ and }j^2 is j*j=j^2.

Now let us find GCF of k^4\text{ and }k^6.

Factors of k^4 are: k*k*k*k    

Factors of k^6 are:k*k*k*k*k*k

We can see that greatest common factor of  k^4\text{ and }k^6 is k*k*k*k=k^4.

Upon combining our all GCFs we will get,

11j^2k^4  

Therefore, GCF of 44j^5k^4\text{ and }121j^2k^6 is 11j^2k^4 and option D is the correct choice.

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1) The domain In interval notation is [0, 20]

2) The range in interval notation is [100, 700]

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