Answer:
The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph
Step-by-step explanation:
we know that
The speed is equal to divide the distance by the time
Let
x -----> the speed of the wind in miles per hour
y ----> the speed of the jet in still air in miles per hour
we know that
<em>With a tailwind</em>

----> equation A
<em>With a headwind</em>

----> equation B
solve the system of equations A and B by elimination
Adds equation A and equation B

<em>Find the value of x</em>



therefore
The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph
Answer: 2000
Step-by-step explanation:
55 multiplied by 20
is equal to 1,100
100 multiplied by 20
is equal to 2000
2000 ppl were surveyed
9514 1404 393
Answer:
1856
Step-by-step explanation:
The numbers given do not have a common difference, but they do have a common ratio:
58/29 = 116/58 = 2
The general term of a geometric sequence with first term a1 and common ratio r is ...
an = a1×r^(n-1)
For this sequence, a1=29 and r=2, so the general term is ...
an = 29×2^(n-1)
Then the 7th term is ...
a7 = 29×2^(7-1) = 29×64 = 1856
The 7th term is 1856.
_____
If you prefer, you can double each term until you have 7 of them.
29, 58, 116, 232, 464, 928, 1856, ...