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pshichka [43]
1 year ago
12

Together Mary, Jane, and Ruth received $30. Mary received $6, Jane received $9, and Ruth received $15. What percent of the $30 d

id Jane receive?
Mathematics
2 answers:
Likurg_2 [28]1 year ago
8 0
Hey there! :D 

So, we know that Jane received $9 out of the $30. 

Divide 9 by 30. 

9/30= .3

Turn that into a percentage. 

.3= 30%

We can check this by finding the other percentages. 

Ruth= 15  15/30= .5 50% 

Mary= 6 6/30= .2 20%

30%+20%+50%= 100% <== this works

I hope this helps!
~kaikers 
almond37 [142]1 year ago
7 0
Total amount = $30

Jane's amount = $9

Percentage of Jane's amount = 9/30 x 100 = 30%

Answer: 30%
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<u>Step-by-step explanation</u>:

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The Formula for the volume of a cone is

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V= 84.78 cm

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75.76% probability that there will be 10 or more customers at this bank in one hour.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

A bank gets an average of 12 customers per hour.

This means that \mu = 12

Find the probability that there will be 10 or more customers at this bank in one hour.

Either there are less than 10 customers, or there are 10 or more. The sum of the probabilities of these events is 1. Then

P(X < 10) + P(X \geq 10) = 1

We want P(X \geq 10)

Then

P(X \geq 10) = 1 - P(X < 10)

In which

P(X < 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9)

So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-12}*12^{0}}{(0)!} \approx 0

P(X = 1) = \frac{e^{-12}*12^{1}}{(1)!} = 0.0001

P(X = 2) = \frac{e^{-12}*12^{2}}{(2)!} = 0.0004

P(X = 3) = \frac{e^{-12}*12^{3}}{(3)!} = 0.0018

P(X = 4) = \frac{e^{-12}*12^{4}}{(4)!} = 0.0053

P(X = 5) = \frac{e^{-12}*12^{5}}{(5)!} = 0.0127

P(X = 6) = \frac{e^{-12}*12^{6}}{(6)!} = 0.0255

P(X = 7) = \frac{e^{-12}*12^{7}}{(7)!} = 0.0437

P(X = 8) = \frac{e^{-12}*12^{8}}{(8)!} = 0.0655

P(X = 9) = \frac{e^{-12}*12^{9}}{(9)!} = 0.0874

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