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pshichka [43]
1 year ago
12

Together Mary, Jane, and Ruth received $30. Mary received $6, Jane received $9, and Ruth received $15. What percent of the $30 d

id Jane receive?
Mathematics
2 answers:
Likurg_2 [28]1 year ago
8 0
Hey there! :D 

So, we know that Jane received $9 out of the $30. 

Divide 9 by 30. 

9/30= .3

Turn that into a percentage. 

.3= 30%

We can check this by finding the other percentages. 

Ruth= 15  15/30= .5 50% 

Mary= 6 6/30= .2 20%

30%+20%+50%= 100% <== this works

I hope this helps!
~kaikers 
almond37 [142]1 year ago
7 0
Total amount = $30

Jane's amount = $9

Percentage of Jane's amount = 9/30 x 100 = 30%

Answer: 30%
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The number of hurricanes hitting the coast of Florida annually has a Poisson distribution with a mean of 0.8. Answer the followi
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Answer:

a) P(X>2)= 1-P(X \leq 2) = 1-[P(X=0)+P(X=1)+P(X=2)]

And we can find the individual probabilities like this:

P(X=0) = \frac{e^{-0.8} 0.8^0}{0!}= 0.4493

P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595

P(X=2) = \frac{e^{-0.8} 0.8^2}{2!}= 0.1438

And replacing we got:

P(X>2)= 1-P(X \leq 2) = 1-[0.4493+0.3595+0.1438]=0.0474

b) P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595

Step-by-step explanation:

Let X the random variable that represent the number of hurricanes hitting the coast of Florida annualle. We know that X \sim Poisson(\lambda=0.8)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this distribution the expected value is the same parameter \lambda=0.8

E(X)=\mu =\lambda=0.8

Part a

For this case we want this probability: P(X>2)

And for this case we can use the complement rule like this:

P(X>2)= 1-P(X \leq 2) = 1-[P(X=0)+P(X=1)+P(X=2)]

And we can find the individual probabilities like this:

P(X=0) = \frac{e^{-0.8} 0.8^0}{0!}= 0.4493

P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595

P(X=2) = \frac{e^{-0.8} 0.8^2}{2!}= 0.1438

And replacing we got:

P(X>2)= 1-P(X \leq 2) = 1-[0.4493+0.3595+0.1438]=0.0474

Part b

Using the probability mass function we have:

P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595

3 0
1 year ago
A baker’s dozen (13) of cookies is on sale for $2.08.
poizon [28]
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Conor has a roll of fence that is 25 feet long. He needs 8 yards of fence to go around a flower bed. Does he have enough fence t
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Answer:

Yes he has enough fence to go round the flower bed.

Step-by-step explanation:

1 yard = 3 feet

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Yes he has enough fence to go round the flower bed.

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ipn [44]

The answer that I got is C=-6

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skad [1K]

Answer:

160m/s

Step-by-step explanation:

The object can hit the ground when t = a; meaning that s(a) = s(t) = 0

So, 0 = -16a² + 400

16a² = 400

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a = √25

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The instantaneous velocity is

v(a) = lim(t->a) [s(t) - s(a)]/[t-a)

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and s(a) = -16a² + 400

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But a = t

So, we have

v(a) = -16lim t->a 2a

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v(a) = -32 * 5

v(a) = -160

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7 0
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