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2 years ago

Which inequality represent all values of x for which the quotient below is defined??

Mathematics

2 answers:

Liono4ka [1.6K]2 years ago

6 0

Answer:

the answer is b. because x is either grater or equal.

guajiro [1.7K]2 years ago

6 0

Answer:

D. $x>0$

Step-by-step explanation:

We have been given a quotient $\sqrt{6x^2}\div\sqrt{4x}$ . We are asked to find an inequality that represents all values of x for which the quotient below is defined.

We can rewrite our given expression as:

$\sqrt{6x^2}\div\sqrt{4x}$

We know that a square root expression is defined for all values of x greater than or equal to 0. We also know that a fraction is defined when its denominator is greater than 0.

So our fraction will be defined for all values of x greater than 0.

$4x>0$

Upon dividing both sides of our inequality by 4, we will get:

$\frac{4x}{4}>\frac{0}{4}$

$x>0$

Therefore, the inequality $x>0$ represents all values of x for which the given quotient is defined and option D is the correct choice.

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Let h(x)=505.5+8e−0.9x . What is h(5) ? rounded to the nearest tenth. any help would be great

Naddik [55]

For this case, the first thing we are going to do is rewrite the function.
We have then:
h (x) = 505.5 + 8 * exp (-0.9 * x)
We evaluate the value of x = 5 in the function.
We have then:
h (5) = 505.5 + 8 * exp (-0.9 * 5)
h (5) = 505.588872
round to the nearest tenth:
h (5) = 505.6
Answer:
the value of h (5) is:
h (5) = 505.6

3 0

2 years ago

Read 2 more answers

A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe

xxMikexx [17]

Answer:

$P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}$

Step-by-step explanation:

For the random variable $N_1$ we define the possible values for this variable on this case $[1,2,3,4,5]$ . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

$5C2 = \frac{5!}{2! (5-2)!}= \frac{5*4*3!}{2! 3!}= \frac{5*4}{2*1}=10$

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable $N_1$ like this:

$P(N_1 = a) = \frac{5-a C 1}{5C2}$

For the distribution of $N_2$ we need to take in count that we are finding a conditional distribution. $N_2$ given $N_1 =a$ , for this case we see that $N_2 \in [1,2,...,5-a]$ , so then exist $5-a C 1$ ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

$P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}$

And if we want to find the joint probability we just need to do this:

$P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)$

And if we multiply the probabilities founded we got:

$P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}$

8 0

2 years ago

a woman is looking for a bigger square office. she finds an office twice the area of her square office. if the perimeter is 88ft

UNO [17]

Answer:

Option C is the correct answer.

Step-by-step explanation:

Perimeter of current office = 88 ft

We have perimeter = 4a , where a is the side of square.

Equating

4a = 88

a = 22 sqft

Area of current office = a x a = 22 x 22 = 484 square feet.

Area of new office is twice the area of current office.

Area of new office = 2 x 484 = 968 square feet.

Option C is the correct answer.

6 0

2 years ago

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there are 6 grams of fat per serving of granola. each serving provides 180 calories. what percentage of these calories is from f

expeople1 [14]

There are 6 grams of fat per serving in granola. 
Each serving provides 180 calories. 
There are 9 calories of fat in each gram. 
The percentage of calories from fat in granola is? 

30%

7 0

2 years ago

Alana is writing a coordinate proof to show that the diagonals of a rectangle are congruent. She starts by assigning coordinates

tamaranim1 [39]

D(S,P) = √(0-0)^2 + √(b-0)^2
d(S,P) = √b^2
d(S,P) = b
so
SP = b

d(P, Q) = √(a-0)^2 + √(b-b)^2
d(P, Q) = √a^2
d(P, Q) = a
so
PQ = a

SQ = c^2 = a^2 + b^2
SQ = √(a^2 + b^2)

answer
the length of one of the diagonals of the rectangle is √(a^2 + b^2)

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2 years ago

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