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stiv31 [10]
1 year ago
7

You found $6.60 on the ground at school, all in nickels, dimes, and quarters. you have twice as many quarters as dimes and 42 co

ins in all. howmany of each type of coin do you have
Mathematics
1 answer:
Veseljchak [2.6K]1 year ago
8 0
Let the number of nickels found be n, the number of dimes be d and the number of quarters be q.

i) "you have twice as many quarters as dimes and 42 coins in all."

means that 2d=q, and n+d+q=42

we can reduce the number of unknowns by substituting q with 2d:

n+d+q=42
n+d+2d=42
n+3d=42

We can write all n, d and q in terms of d as follows:

there are n=42-3d nickels, d dimes and q=2d quarters.

ii) In total there are $6.60 dollars,

1 nickel     =  5 cent   =  $0.05
1 dime      =  10 cent  =  $0.1
1 quarter   =  25 cent  = $0.25 

thus

(42-3d)*0.05 + d*0.1 +2d*0.25= $6.60

2.1 - 0.15d+0.1d+0.5d=6.60

2.1+0.45d=6.6

0.45d=6.6-2.1=4.5

d=4.5/0.45=10

iii)

so, there are 10 dimes, 2d=2*10=20 quarters and 42-3d=42-3*10=12 nickels.


Answer: 10 dimes, 20 quarters, 12 nickels
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jasenka [17]

When you think of the situation as a whole, you may notice that the lines in the problem actually form a triangle. First, the man driving 10 miles east forms a bottom leg of the triangle 10 units long. When he drives the 2 miles north, he adds another leg of 2 units length. When the place of work is connected to the starting position through a line, a third and final line is drawn which creates the triangle.


So, how can we find the direct distance from his place of work to his home? We can use the Pythagorean Theorem (a^2 + b^2 = c^2, where a and b are the lengths of the legs of the triangle and c is the length of the hypotenuse). We know that the lengths of the legs are 10 and 2, which we can use in the formula, as shown below:

(10)^2 + (2)^2 = c^2


Now, we can solve this equation for c:

\sqrt{(10)^2 + (2)^2} = c

\sqrt{104} = c \approx 10.2


The distance would be √104 miles, or approximately 10.2 miles.

4 0
2 years ago
In Boston taxicabs charge an initial fare and an additional amount for every mile traveled. Tahira is having trouble figuring ou
nlexa [21]

Answer:

The taxi charges $2.5 for every mile.

Step-by-step explanation:

We are given the following in the question:

Let x be the initial taxicab fare and y be the additional amount for every mile traveled.

Cost for a two mile ride = $7.00

Thus, we can write the equation:

x + 2y = 7

Cost of a nine mile ride = $24.50

Thus, we can write the equation,

x + 9y = 24.50

Solving the two equation by elimination method, we have,

x + 9y - (x + 2y) = 24.50 - 7\\7y = 17.5\\y = 2.5\\\Rightarrow x + 2(2.5) = 7\\x = 2

Thus, $2 is the initial fare and $2.5 is the cost for every mile traveled.

3 0
1 year ago
Find the distance from (4, −7, 6) to each of the following.
LenKa [72]

Answer:

(a) 6 units

(b) 4 units

(c) 7 units

(d) 9.22 units

(e) 7.21 units

(f) 8.06 units

Step-by-step explanation:

The distance d from one point (x₁, y₁, z₁) to another point (x₂, y₂, z₂) is given by;

d = √[(x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²]

Now from the question;

<em>(a) The distance from (4, -7, 6) to the xy-plane</em>

The xy-plane is the point where z is 0. i.e

xy-plane = (4, -7, 0).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(4, -7, 0)</em>

d = √[(4 - 4)² + (-7 - (-7))² + (0 - 6)²]

d = √[(0)² + (0)² + (-6)²]

d = √(-6)²

d = √36

d = 6

Hence, the distance to the xy plane is 6 units

<em>(b) The distance from (4, -7, 6) to the yz-plane</em>

The yz-plane is the point where x is 0. i.e

yz-plane = (0, -7, 6).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(0, -7, 6)</em>

d = √[(4 - 0)² + (-7 - (-7))² + (6 - 6)²]

d = √[(4)² + (0)² + (0)²]

d = √(4)²

d = √16

d = 4

Hence, the distance to the yz plane is 4 units

<em>(c) The distance from (4, -7, 6) to the xz-plane</em>

The xz-plane is the point where y is 0. i.e

xz-plane = (4, 0, 6).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(4, 0, 6)</em>

d = √[(4 - 4)² + (-7 - 0)² + (6 - 6)²]

d = √[(0)² + (-7)² + (0)²]

d = √[(-7)²]

d = √49

d = 7

Hence, the distance to the xz plane is 7 units

<em>(d) The distance from (4, -7, 6) to the x axis</em>

The x axis is the point where y and z are 0. i.e

x-axis = (4, 0, 0).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(4, 0, 0)</em>

d = √[(4 - 4)² + (-7 - 0)² + (6 - 0)²]

d = √[(0)² + (-7)² + (6)²]

d = √[(-7)² + (6)²]

d = √[(49 + 36)]

d = √(85)

d = 9.22

Hence, the distance to the x axis is 9.22 units

<em>(e) The distance from (4, -7, 6) to the y axis</em>

The x axis is the point where x and z are 0. i.e

y-axis = (0, -7, 0).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(0, -7, 0)</em>

d = √[(4 - 0)² + (-7 - (-7))² + (6 - 0)²]

d = √[(4)² + (0)² + (6)²]

d = √[(4)² + (6)²]

d = √[(16 + 36)]

d = √(52)

d = 7.22

Hence, the distance to the y axis is 7.21 units

<em>(f) The distance from (4, -7, 6) to the z axis</em>

The z axis is the point where x and y are 0. i.e

z-axis = (0, 0, 6).

Therefore, the distance d is from <em>(4, -7, 6) </em> to <em>(0, 0 6)</em>

d = √[(4 - 0)² + (-7 - (0))² + (6 - 6)²]

d = √[(4)² + (-7)² + (0)²]

d = √[(4)² + (-7)²]

d = √[(16 + 49)]

d = √(65)

d = 8.06

Hence, the distance to the z axis is 8.06 units

5 0
2 years ago
in june , a camp has 325 campers and 26 counselors, in july,265 campers leave and 215 new campersarrive.How many counselors does
Lostsunrise [7]

Answer:

  • <u>22 counselors</u>

<u></u>

Explanation:

<u>1. Ratio of campers to counselors in june:</u>

  • number of campers: 325

  • number of counselors: 26

  • Ratio = number of campers / number of counselors

  • Ratio = 325 campers / 26 counselors

<u />

<u>2. Ratio of campers to counselors in july:</u>

  • number of campers = 325 - 265 + 215 = 275

  • number of counselors = x (unknown)

  • Ratio = 275 campers / x

<u />

<u>3. Equivalent ratios:</u>

  • 325 campers / 26 counselors = 275 campers / x

Solve for x:

  • x = (26counselors/325campers) × 275campers = 22 counselors ← answer

3 0
1 year ago
Drag the cards to create a two-digit number that matches these rules. Note: Not all cards will be used 6 is one of the digits 20
Greeley [361]

Answer:

As i understand this:

We have cards with the values:

0, 1, 2 and 6.

We want to create a two digit number such that:

Not all the cards are used.

6 is one digit of our number.

When we round to the nearest ten, we get 20.

Now, first remember how rounding works.

If we have a number like ab, where a and b are single digits (a is in the tens place and b is in the units place), then:

if b is 5 or more, we round up

if b is less than 5, we round down.

Now in this case we want to have a digit equal 6, if we use this in the units place, then when rounding, we will round up.

Then the other digit can be 1, such that we use the cards:

1 and 6.

then our number is 16:

When rounding, 6 > 5, then we round up to 20.

So this number meets all the conditions.

3 0
1 year ago
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