The square shown has a perimeter of 32 units. The square is rotated about line k.
2 answers:
A cylinder with a circumference of about 50 units is formed.
Step-by-step explanation:
Step 1:
The perimeter of the square is 32 units. The perimeter of a square is given by 4 times its side length.
So the side length of the square is 8 units.
If a square is rotated a cylinder will be formed. So the options with a cone are wrong as a cone is formed when a triangle is rotated.
Step 2:
To calculate the circumference of the cylinder, we multiply 2π with the radius. The radius is the same as the side length of the square. So r is 8 units.
The circumference of the cylinder
So the circumference of the cylinder is approximately equal to 50 units so the answer is the fourth option, a cylinder with a circumference of about 50 units.
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Answer:
Step-by-step explanation:
Given
Straight Line, PS
Such that
Required
Find PS
From the attachment above, it can be seen that RS is a continuation of PS;
This implies that
Substitute and
Collect like terms
Hence, the length of PS is
To solve this problem you must apply the proccedure shown below:
1. We know that 1 yard is 36 inches, therefore, 50 yards expressed in inches is:
2. If he is 50 yards from school and the map shows that the school is 34 inches from his current location, when it shows 3 inches the real distance is:
3. If you can to express it in yards:
Therefore, the answer is: 158.82 inches or 4.41 yards.
Answer:
The following points are not arranged in a parallelogram or rectangle order.
Step-by-step explanation:
Well first we need to graph the following.
A(1,1) B(2,2) C(3,3) D(4,4)
By looking at the image below we can tell it is not any shape, it’s not a parallelogram or a rectangle.
It is a line with a slope of 1 or x.
Answer:
A. Initially, there were 12 deer.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. After 15 years, there will be 410 deer.
D. The deer population incresed by 30 specimens.
Step-by-step explanation:
The amount of deer that were initally in the reserve corresponds to the value of N when t=0
A. Initially, there were 12 deer.
B.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C.
C. After 15 years, there will be 410 deer.
D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:
ΔN=N(15)-N(10)
ΔN=410 deer - 380 deer
ΔN= 30 deer.
D. The deer population incresed by 30 specimens.