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Damm [24]
1 year ago
15

A faucet is leaking water at a rate of 2.5 cups per hour. How many cups of water will leak in 8 hours? A. 3.2

Mathematics
2 answers:
GREYUIT [131]1 year ago
4 0

Answer:

D) 20 cups

Step-by-step explanation:

2.5×8

VikaD [51]1 year ago
3 0

Answer:

20

Step-by-step explanation:

In 8 hours, it will leak 2.5 * 8 = 20 cups of water.

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The sides of a square are three to the power of two sevenths inches long. What is the area of the square? (
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Answer:

Step-by-step explanation:

The side of the square = 3^2/7

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3^2/7 = 3^2 x 1/7 = 7√9

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This gives you 1.87...

Hope this helps

8 0
2 years ago
Almonds cost $5.20 per pound Raisins cost $2.75 per pound Priya spent $11.70 of buying almonds & raisins Equation: 5.20+2.75
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Answer:

If she bought 2lbs of almonds, she bought 0.4lbs of raisins. If she bought  1lb of almonds, she can buy up to 2.36lbs of raisins. If she bought 0.64lbs of almonds, she can buy up to 1.9lbs of almonds.

Step-by-step explanation:

6 0
2 years ago
It costs $3 to bowl a game and $2 for shoe rental. a. Write an expression for the total cost (in dollars) of $g$ games. Expressi
Semmy [17]

Answer: a. Total cost = 3g+2

b. The total cost of 8 games is $26.

Step-by-step explanation:

Given: Cost to bowl a game = $3

Shoe rental charge = $2  (One -time charge)

Total cost = (Cost to bowl a game) x (Number of games)+ (Shoe rental charge )

Let g= number of games, then the expression to find the total cost will be :

Total cost = 3g+2

To find the total cost of 8 games, put g=8, we get

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7 0
1 year ago
Two processes are used to produce forgings used in an aircraft wing assembly. Of 200 forgings selected from process 1, 10 do not
tangare [24]

Answer:

a.

\bar p_1=0.05\\\bar p_2=0.067

b-Check illustration  below

c.(-0.0517,0.0177

Step-by-step explanation:

a.let p_1  \& p_2 denote processes 1 & 2.

For p_1: T1=10,n1=200

For p_2:T2=20,n2=300

Therefore

\bar p_1=\frac{t_1}{N_1}=\frac{10}{200}=0.05\\\bar p_2=\frac{t_2}{N_2}=\frac{20}{300}=0.067

b. To test for hypothesis:-

i.

H_0:p_1=p_2\\H_A=p_1\neq p_2\\\alpha=0.05

ii.For a two sample Proportion test

Z=\frac{\bar p_1-\bar p_2}{\sqrt(\bar p(1-\bar p)(\frac{1}{n_1}+\frac{1}{n_2})}\\

iii. for \frac{\alpha}{2}=(-1.96,+1.96) (0.5 alpha IS 0.025),

reject H_o if|Z|>1.96

iv. Do not reject H_o. The noncomforting proportions are not significantly different as calculated below:

z=\frac{0.050-0.067}{\sqrt {(0.06\times0.94)\times \frac{1}{500}}}

z=-0.78

c.(1-\alpha).100\% for the p1-p2 is given as:

(\bar p_1-\bar p_2)\pm Z_0_._5_\alpha \times \sqrt   \frac{ \bar p_1(1-\bar p_1)}{n_1}+\frac{\bar p_2(1-\bar p_2)}{n_2}\\\\=(0.05-0.067)\pm 1.645  \times \sqrt \ \frac{0.05+0.95}{200}+\frac{0.067+0.933}{300}\\

=(-0.0517,+0.0177)

*CI contains o, which implies that proportions are NOT significantly different.

4 0
2 years ago
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