To approximate the measure of angle D, we will need to use the inverse cosine function on our calculator. All calculators vary, so I am not sure where you would find the button for it on your calculator. However, I know many calculators have it so you click the second button, then cos.
cos(D) = 0.33
D = cos^-1 (0.33)
D = 70.7 degrees
Hope this helps!! :)
If two chords of a circle are congruent, then their intercepted arcs are congruent
7x-39 = 87
7x = 87 + 39
7x = 126
x = 126/7
x = 18
If the adjusted ratio was 2:7, then
2x is the number of pull-ups
and
7x is the number of box jumps.
You can state that since he completed 63 box jumps at the end of his training, then
7x=63,
x=9
and
2x=18.
The total number of exercises performed is 2x+9x=18+63=81.
As at start the ratio was 5:4, then
5y was the number of pull-ups
and
4y was the number of box jumps.
Therefore, 5y+4y=81,
9y=81,
y=9
and 5y=45, 4y=36.
Answer: Initially: 45 pull-ups and 36 box jumps. At the end: 18 pull-ups and 63 box jumps.
The given complex number is
z = 1 + cos(2θ) + i sin(2θ), for -1/2π < θ < 1/2π
Part (i)
Let V = the modulus of z.
Then
V² = [1 + cos(2θ)]² + sin²(2θ)
= 1 + 2 cos(2θ) + cos²2θ + sin²2θ
Because sin²x + cos²x = 1, therefore
V² = 2(1 + cos2θ)
Because cos(2x) = 2 cos²x - 1, therefore
V² = 2(1 + 2cos²θ - 1) = 4 cos²θ
Because -1/2π < θ < 1/2π,
V = 2 cosθ PROVEN
Part ii.
1/z = 1/[1 + cos2θ + i sin 2θ]

The denominator is

Therefore

The real part of 1/ = 1/ (constant).
Answer: Hello the scatter plot related to your question is missing attached below is the scatter plot
answer : The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship ( C )
Step-by-step explanation:
The conclusion that can be drawn based upon the scatter chart is that The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship
<em>A scatter plot helps in observing the relationship within different numeric variables but the scatter plot attached fails in the showing the actual relationship </em>