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Free_Kalibri [48]
2 years ago
13

The range of which function is (2, infinity)? y = 2x y = 2(5x) y = 5x +2 y = 5x + 2

Mathematics
2 answers:
Arturiano [62]2 years ago
5 0

Answer:

y = 5∧× + 2

Step-by-step explanation:

Sveta_85 [38]2 years ago
3 0

Answer:

I think your functions are y=2^{x} ,y=2*5^{x} and y=2+5^{x}

If yes then then the third function which is y=2+5^{x}.

Step-by-step explanation:

The function c^{x} where c is a constant has

Domain : c\geq 0

Range : ( 0 , ∞ )

The above range is irrespective of the value of c.

I have attached the graph of each of the function, you can look at it for visualization.

  • <em>y=2^{x} ⇒ </em>This function is same as  c^{x} so its range is <em>( 0 , ∞ )</em>.
  • <em>y=2*5^{x} ⇒ </em>If we double each value of the function y=5^{x}, which has range ( 0 , ∞ ), but still the value of extremes won't change as 0*2=0 and ∞*2=∞. Therefore the range remains as <em>( 0 , ∞ )</em>.
  • <em>y=2+5^{x}</em> ⇒ If we add 2 to each value of the function y=5^{x}, which has range ( 0 , ∞ ), the lower limit will change as 0+2=2 but the upper limit will be same as ∞. Therefore the range will become as <em>( 2 , ∞ )</em>.

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