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ipn [44]
2 years ago
5

The quadratic function f has a vertex at (3,4) and opens upward. The quadratic function g is shown below as g(x)=2(x-4)2+3. Whic

h statement is true?  A. The maximum value of f is greater than the maximum value of g. B. The minimum value of f is greater than the minimum value of g. C. The maximum value of g is greater than the maximum value of f. D. The minimum value of g is greater than the minimum value of f.
Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
7 0

The vertex coordinates of g(x) is (4,3). Indeed, the function is given as g(x)=2(x-4)^{2}+3 and when we set x = 4, then g(x) = 3 because the function is given in a closed form. In g(x) and f(x) the values 3 and 4 respectively are the minimum values. The functions are going upward. The value of f(x) is above the value of g(x). The correct answer is B

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The student should have divided the discounted amount by the percent. The percent should have been written as a decimal.

Step-by-step explanation:

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A race car driver lost 8 seconds off the leader for each of the 3 pit stops the driver made. At each of the next 2 pit stops the
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Find the sum of 67.008 and 3.8
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Answer:

69.808

Step-by-step explanation:

69.808

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2 years ago
Alicia sews costumesfor a school play.She takes an average of 86 minutes to sew each costume.How long would she take to sew 16 o
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Answer:

1376 minutes

Step-by-step explanation:

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3 0
2 years ago
The extract of a plant native to Taiwan has been tested as a possible treatment for Leukemia. One of the chemical compounds prod
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Answer:

a) 57.35%

b) 99.99%

c) 68.27%

Step-by-step explanation:

When we have a random variable X that is normally distributed with mean \large\bf \mu and standard deviation \large\bf \sigma, then  

The probability that the random variable has a value less than a, P(X < a) = P(X ≤ a) is the area under the normal curve with mean \large\bf \mu and standard deviation \large\bf \sigma to the left of a.

The probability that the random variable has a value greater than b, P(X > b) = P(X ≥ b) is the area under the normal curve with mean \large\bf \mu and standard deviation \large\bf \sigma to the right of b.

The probability that the random variable has a value between a and b, P(a < X < b) = P(a ≤ X ≤  b) = P(a < X ≤  b)= P(a ≤ X < b) is the area under the normal curve with mean \large\bf \mu and standard deviation \large\bf \sigma between a and b.

In this case, the random variable is the collagen amount found in the extract of the plant. The mean is 63 g/ml and the standard deviation is 5.4 g/ml

(a) What is the probability that the amount of collagen is greater than 62 grams per mililiter?

As we have seen, we need to find the area under the normal curve with mean 63 and standard deviation 5.4 to the right of 62 (see picture).

You can find this value easily with a calculator or a spreadsheet. If you prefer the old-style, then you have to standardize the values and look up in a table.

<em>If you have access to Excel or OpenOffice Calc, you can find this value by introducing the formula: </em>

<em>1- NORMDIST(62,63,5.4,1) in Excel </em>

<em>1 - NORMDIST(62;63;5.4;1) in OpenOffice Calc </em>

<em>and we will get a value of 0.5735 or 57.35% </em>

(b) What is the probability that the amount of collagen is less than 90 grams per mililiter?

Now we want the area to the left of 90

<em>NORMDIST(90,63,5.4,1) in Excel </em>

<em>NORMDIST(90;63;5.4;1) in OpenOffice Calc </em>

You will get a value of 0.9999 or 99.99%

(c) What percentage of compounds formed from the extract of this plant fall within 1 standard deviations of the mean?

You can use either the rule that 68.27% of the data falls between \large\bf \mu -\sigma and \large\bf \mu +\sigma or compute area between 63 - 5.4 and 63 + 5.4, that is to say, the area between 57.6 and 68.4  

<em>In Excel </em>

<em>NORMDIST(68.4,63,5.4,1) - NORMDIST(57.6,63,5.4,1)  </em>

<em>In OpenOffice Calc  </em>

<em>NORMDIST(68.4;63;5.4;1) - NORMDIST(57.6;63;5.4;1)  </em>

In any case we get a value of 0.6827 or 68.27%

3 0
2 years ago
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