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Umnica [9.8K]
2 years ago
11

WXYZ is a trapezoid with WX ≅ YZ. Isosceles trapezoid W X Y Z is shown. Sides X Y and W Z are parallel. The length of X Y is 3 a

minus 4 and the length of W Z is 3 a. Sides W X and Y Z are congruent. The length of W X is 2 a minus 2 and the length of Y Z is a + 1. What is the length of XY? 3 units 4 units 5 units 6 units
Mathematics
2 answers:
mash [69]2 years ago
8 0

Answer: 5 units

Step-by-step explanation:

kykrilka [37]2 years ago
6 0

Answer:

5

Step-by-step explanation:

You might be interested in
Suppose that the duration of a particular type of criminal trial is known to be normally distributed with a mean of 21 days and
Black_prince [1.1K]

Answer:

0.33411

The probability that a particular criminal trial lasted atleast 24 days is 0.33411

Step-by-step explanation:

The random variable X is normally distributed with a mean of 21 and standard deviation of 7

;

X ~ N(μ = 21 ; σ = 7)

X ~ N(21, 7)

Probability that a trial lasted atleast 24 days :

P(X ≥ 24) :

The standardized score :

Z = (x - μ) / σ ; (24 - 21) / 7 ; 3 / 7 = 0.4286

Hence,

P(Z ≥ 0.4286) = 0.33411

The probability that a particular criminal trial lasted atleast 24 days is 0.33411

6 0
2 years ago
The amounts of vitamin C (in milligrams) for 100g (3.57 ounces) of various randomly selected fruits and vegetables are listed. I
34kurt

Answer:

H0: sigma=12

H1:sigma≠12

This hypothesis test is a two tailed test.

Step-by-step explanation:

The null value described in the statement is 12 mg. So, the null hypothesis would be sigma=12. As the statement states that whether there is sufficient evidence to conclude that standard deviation differs from 12 mg, so the alternative hypothesis would be sigma ≠12. The alternative hypothesis contains inequality sign so, the hypothesis test is a two tailed test.

4 0
2 years ago
A radar gun was used to record the speed of a swimmer (in meters per second) during selected times in the first 2 seconds of a r
Natalka [10]
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]

the area of each trapezoid is (v(t1)+v(t2))/2 times width

for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8

2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24

3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75

4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7

add them all up
0.8+2.24+1.75+0.7=5.49

5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
8 0
2 years ago
K is the midpoint of segment HL . H has coordinates (1, -7 ) , and K has coordinates(-9, 3 ). Find the coordinates of other end
Andrei [34K]

Answer:

Coordinates of other end point L = ( -19, 13 )

Explanation:

 The mid point of the coordinates (a,b) and (c,d) is given by (\frac{a+c}{2},\frac{b+d}{2})

 Here we have (a,b) = (1,-7) and (\frac{a+c}{2},\frac{b+d}{2}) = (-9,3) , we need to find (c,d).

 \frac{a+c}{2} =-9\\ \\ 1+c=-18\\ \\ c=-19\\\\ \frac{b+d}{2} =3\\ \\ -7+d=6\\ \\ d=13

So coordinates of other end point L = ( -19, 13 )

8 0
2 years ago
Read 2 more answers
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
7nadin3 [17]

The equation of the cone should be z=\sqrt{x^2+y^2}. Parameterize S by

\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+u\,\vec k

with 1\le u\le2 and 0\le v\le2\pi. Take the normal vector to S to be

\vec s_v\times\vec s_u=u\cos v\,\vec\imath+u\sin v\,\vec\jmath-u\,\vec k

Then the integral of \vec F across S is

\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_1^2(-u\cos v\,\vec\imath-u\sin v\,\vec\jmath+u^3\,\vec k)\cdot(u\cos v\,\vec\imath+u\sin v\,\vec\jmath-u\,\vec k)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{2\pi}\int_1^2(-u^2-u^4)\,\mathrm du\,\mathrm dv

=\displaystyle-2\pi\int_1^2(u^2+u^4)\,\mathrm du\,\mathrm dv=\boxed{-\frac{256\pi}{15}}

3 0
2 years ago
Read 2 more answers
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