Answer:
14.04 miles per hour
Step-by-step explanation:
The problem is asking for Izumi's speed. The formula of speed is:
- s =
, where "s" means speed, "d" means distance and "t" means time.
The problem is also asking for the unit<u> miles per hou</u>r (
) so, this means that we have to know how many miles Izumi ran, given that the problem only mentioned<u> yards (110 yards).</u>
Let's convert 110 yards to miles, provided that he Izumi ran 1,760 yards in a mile.
- 110 yards ÷ 1760
= 0.0625 miles (this is the distance covered by Izumi in miles)
Let's go back again to the formula: s = 
s =
= 0.0039 
Since, the we arrived at a miles per second unit, we have to convert it to miles per hour.
So, if a minute has 60 seconds, then an hour has 3,600 seconds.
Thus, 0.0039
× 3,600
= 14.04 miles per hour (the answer)
12 1/4 feet wide stream so it is 1 feet and 9 inches shorter
Answer:
Option (B)
Step-by-step explanation:
Given polynomial in the question is,
x³ - 7x² + 13x - 3
One factor of the polynomial is (x - 3).
That means x = 3 is a zero factor of the polynomial.
For the other factor,
By using synthetic division,
3 | 1 -7 13 -3
<u> 3 -12 3 </u>
1 -4 1 0
= (x² - 4x + 1)(x - 3)
Therefore, the other factor of the polynomial is (x² - 4x + 1).
Option (B) will be the answer.
Answer:
113.04square feet
Step-by-step explanation:
square root of 144 is 12
use it as the dimensions of the plot.
the flower gardens largest possible diameter is 12
so divide 12 by a half
6=radius
3.14 times 6squared
you get 113.04
Answer:
765 J
Step-by-step explanation:
We are given;
Mass of bucket = 30 kg
Mass of rope = 0.3 kg/m
height of building= 30 meter
Now,
work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand
Or W = W1 + W2
Work done in lifting the rope is given as,
W1 = Force x displacement
W1 = (30,0)∫(0.2x .dx)
Integrating, we have;
W1 = [0.2x²/2] at boundary of 30 and 0
W1 = 0.1(30²)
W1 = 90 J
work done in lifting the sand is given as;
W2 = (30,0)∫(F .dx)
F = mx + c
Where, c = 30 - 15 = 15
m = (30 - 15)/(30 - 0)
m = 15/30 = 0.5
So,
F = 0.5x + 15
Thus,
W2 = (30,0)∫(0.5x + 15 .dx)
Integrating, we have;
W2 = (0.5x²/2) + 15x at boundary of 30 and 0
So,
W2 = (0.5 × 30²)/2) + 15(30)
W2 = 225 + 450
W2 = 675 J
Therefore,
work done lifting the bucket (sand and rope) to the top of the building,
W = 90 + 675
W = 765 J