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2 years ago

11

Delia went to a market to buy 4.5 pounds of sliced fruit in a container she paid with a $20 bill and a $5 bill and received $4.6

7 as change she paid $1.62 in taxes for the fruit what waa the cost for one pound of sliced fruit before taxes?

1 answer:

andreyandreev [35.5K]2 years ago

4 0

20+5=25 then 25-4.67=20.33 so then you do 20.33/4.5=4.5 so the cost for one pound of fruit is $4.57. Hope this helps :)

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Find the values of x1 and x2 where the following two constraints intersect.

Arte-miy333 [17]

Answer: x1 = 251/26, x2 = -111/26

Step-by-step explanation:

Hi!

As you can see in the figure, the point you are looking for is the intersection of two lines.

The intersection point is found solving this system of linear equations (the point must satisfy both equations):

$9x_1 +7x_2=57\\4x_1 + 6x_2 = 13$

You can solve it, for example, by the method of substitution:

$\text{solve for x1 in the first equation:}\\x_1 = \frac{1}{9}(57 - 7x_2)$

Then plug x1 into equation 2, and solve for x2:

$\frac{4}{9}(57-7x_2) + 6x_2 = 13\\\text{doing the algebra you get:}\\x_2 = \frac{-111}{26}$

Then you use the value of x2 to get x1:

$x_1 = \frac{1}{9}(57 - 7x_2)= \frac{1}{9}(57 + 7*\frac{111}{26}) = 251/26\\$

4 0

2 years ago

Jesus wants to start saving for college. His parents started an account for him that currently holds $325. Jesus adds $50 each m

erma4kov [3.2K]

Answer:

y-intercept, c = 325

Slope, m = 50

The x-axis represents the number of months and y-axis represents the total amount in saving accounts.

Step-by-step explanation:

We are given the following in the question:

A saving account currently holds $325. Jesus adds $50 each month.

Let x be the number of months and y be the total money n the saving account.

Then, we can use a linear function to represent the money in the account.

$y(x) = 325 + 50x$

Comparing to general linear function,

$y = mx + c$

where m is the slope and tells the rate of change and c is the y-intercept that is the value when x is zero.

Comparing we get:

m = 50

c = 325

y-intercept = c = 325

Slope, m = 50

The x-axis represents the number of months and y-axis represents the total amount in saving accounts.

The attached image shows a graph for the same.

7 0

1 year ago

Which of the following is an equivalent form of the compound inequality −33 > −3x − 6 ≥ −6?

wolverine [178]

<u>ANSWER</u>

$9\: < x \leqslant0$

<u>EXPLANATION</u>

The given compound inequality is

$- 33 \: > - 3x - 6 \geqslant - 6$

We need to simplify this inequality so that we can obtain x standing alone between the inequality signs.

We add 6 through out the inequality.

$- 33 + 6\: > - 3x - 6 + 6 \geqslant - 6 + 6$

This simplifies to:

$- 27\: > - 3x \geqslant 0$

We now divide through by -3 and reverse the inequality sign.

$\frac{- 27}{ - 3} \: < \frac{ - 3x}{ - 3} \leqslant \frac{0}{ - 3}$

We now simplify to get:

$9\: < x \leqslant 0$

6 0

2 years ago

A dormitory has 40 students---12 sophomores, 8 juniors, and 20 seniors. Which of the following is equal to the number of ways to

Maurinko [17]

Answer:

The number of ways is equal to $12!8!20!$

Step-by-step explanation:

The multiplication principle states that If a first experiment can happen in n1 ways, then a second experiment can happen in n2 ways ... and finally a i-experiment can happen in ni ways therefore the total ways in which the whole experiment can occur are

n1 x n2 x ... x ni

Also, given n-elements in which we want to put them in a row, the total ways to do this are n! that is n-factorial.

For example : We want to put 4 different objects in a row.

The total ways to do this are $4!=4.3.2.1=24$ ways.

Using the multiplication principle and the n-factorial number :

The number of ways to put all 40 in a row for a picture, with all 12 sophomores on the left,all 8 juniors in the middle, and all 20 seniors on the right are : The total ways to put all 12 sophomores in a row multiply by the ways to put the 8 juniors in a row and finally multiply by the total ways to put all 20 senior in a row ⇒ $12!8!20!$

4 0

2 years ago

Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes

Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2 $\times$ 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 $\times$ 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled $\triangle AOB$ .

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units$

so, the total distance between the two boats is 74.28 units.

Change in distance per hour = $\dfrac{Total\ distance}{Total\ time}$

$\Rightarrow \dfrac{74.28}{5} = 14.86\ knots$

6 0

1 year ago