2 years ago

Make w the subject of the formula y-aw=2w-1

1 answer:

6 0

Answer: <span>w = [ y + 1] / [a + 2]

Solution step by step:
</span>
1) given <span>formula: y-aw=2w-1

2) transpose aw and - 1

2w + aw = y + 1

3) common factor w:

w (a + 2) = y + 1

4) divide both sides by (a + 2):

w = [ y + 1] / [a + 2]
</span>

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Answer:

a) About 12%

Step-by-step explanation:

We need to find the interest rate required to achieve her goal, so we will need to use the interest-compound formula:

$FV=PV(1+i)^{n}$

Where:

PV= Present Value

i= interest rate

FV= Future Value

n= number of periods

replacing the data provided:

$150.000=50.000(1+i)^{10}$

solving for i:

first, divide both sides by 50.000 to simplify the equation:

$3=(1+i)^{10}$

Take $10^{th}$ roots of both sides:

$1+i=$ ± $\sqrt[10]{3}$

solve for i:

$i=$ ± $\sqrt[10]{3} -1$

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2 years ago

A shark began at 172.5 meters below sea level and then swam up 137.1 meters where is the sharks location now relation to sea lev

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Answer:34.4

Step-by-step explanation:

172.5-137.1=34.4

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2 years ago

On a coordinate plane, parallelogram P Q R S is shown. Point P is at (negative 2, 5), point Q is at (2, 1), point R is at (1, ne

Oksanka [162]

Answer:

The perimeter is $(8\sqrt{2}+2\sqrt{10})\ units$

Step-by-step explanation:

we know that

A parallelogram is a quadrilateral where both pairs of opposite sides are parallel and equal

In this problem

PS=QR ----> equation A

SR=PQ ----> equation B

The perimeter of parallelogram PQRS is

P=PQ+QR+SR+PS ----> equation C

substitute equation A and equation B in equation C

$P=2SR+2QR$

we have

$QR=\sqrt{10}\ units$

$SR=4\sqrt{2}\ units$

substitute in the formula of perimeter

$P=2(4\sqrt{2})+2(\sqrt{10})$

$P=(8\sqrt{2}+2\sqrt{10})\ units$

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2 years ago

Read 2 more answers

Janelle practices basketball every afternoon in the driveway each day her goal is to make four more baskets then she made the da

Alla [95]

She made 62 baskets by day 14. 4×13=52+10=62

5 0

2 years ago

If the instructions for a problem ask you to use the smallest possible domain to completely graph two periods of y = 5 + 3 cos 2

erica [24]

Hello,

y=5+3*cos (2(x-π/3))

The function is periodic with periode=2π.

-1<=cos (2(x-π/3))<=1
==>-1*3<=3*cos (2(x-π/3))<=3*1
==>5-3<=5+3cos(2(x-π/3))<=5+3
==>2<= y<=8

8 0

2 years ago