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shepuryov [24]
2 years ago
6

Make w the subject of the formula y-aw=2w-1

Mathematics
1 answer:
kipiarov [429]2 years ago
6 0
Answer: <span>w = [ y + 1] / [a + 2]

Solution step by step:
</span>
1) given <span>formula: y-aw=2w-1

2) transpose aw and - 1

2w + aw = y + 1

3) common factor w:

w (a + 2) = y + 1

4) divide both sides by (a + 2):

w = [ y + 1] / [a + 2]
</span>
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Vector bought 15.6 pounds of paintballs. all together, the balls cost 35.99. About how much dis the psinballs cost per pond?
nevsk [136]
Paintballs are $2.30 per pound.
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2 years ago
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A university is trying to determine what price to charge for tickets to football games. At a price of ​$ per​ ticket, attendance
Anika [276]

This question is incomplete, the complete question is;

A university is trying to determine what price to charge for tickets to football games. At a price of ​$24 per​ ticket, attendance averages 40,000 people per game. Every decrease of ​$4 adds 10,000 people to the average number. Every person at the game spends an average of ​$4 on concessions. What price per ticket should be charged in order to maximize​ revenue? How many people will attend at that​ price?

Answer:

a) price per ticket = $18

b) 55,000 will attend at that price

Step-by-step explanation:

Given that;

price of ticket = $24

so cost of ticket = 24 - x

every decrease of $4 adds 10,000 people

for $1 adds 2,500 people

Total people = 40000 + 2500x

Revenue function = people × cost + people × 4

so

R(x) = (40000 + 2500x)(24 - x) + (40000 + 2500x)4

R(x) = 960,000 - 40000x + 60000x - 2500x² + 160,000 + 10000x

R(x) = 1120000 + 30000x - 2500x²

R(x) = -2500x² + 30000x + 1120000

now for maximum revenue; R'(x) is to zero

so

R'(x) = d/dx(  -2500x² + 30000x + 1120000 ) = 0

⇒ -5000x + 30000 + 0 = 0

⇒ -5000x + 30000 = 0

⇒ 5000x = 30000

x = 30000 / 5000

x = 6

R'(X) = -5000 < 0 ⇒ MAXIMUM

∴ Revenue is maximum at x = 6

so cost of ticket ;

price per ticket = (24 - x) = 24 - 6 = $18

so price per ticket = $18

Number of people = 40000 + 2500x

= 40000 + (2500 × 6)

= 40000 + 15,000

= 55,000

Therefore, 55,000 will attend at that price

8 0
1 year ago
An airplane travels at 950 km/h. how long does it take to travel 1.00km? in hours
Kay [80]
<span>An airplane travels at 950 km/h. how long does it take to travel 1.00km? in hours, 0.0010526 hrs.</span>
6 0
2 years ago
Jack works as a waiter and is keeping track of the tips he earns daily. About how much does Jack have to earn in tips on
Ray Of Light [21]

Answer:

25$

Step-by-step explanation:

Add all of the days up and divide by 7

7 0
2 years ago
There are 360 people in my school. 15 take calculus, physics, and chemistry, and 15 don't take any of them. 180 take calculus. T
lesantik [10]

Answer:

150 students take physics.

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that take calculus.

-The set B represents the students that take physics

-The set C represents the students that take chemistry.

-The set D represents the students that do not take any of them.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of students that take only calculus, A \cap B is the number of students that take both calculus and physics, A \cap C is the number of students that take both calculus and chemistry and A \cap B \cap C is the number of students that take calculus, physics and chemistry.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C), D

There are 360 people in my school. This means that:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) + D = 360

The problem states that:

15 take calculus, physics, and chemistry, so:

A \cap B \cap C = 15

15 don't take any of them, so:

D = 15

75 take both calculus and chemistry, so:

A \cap C = 75

75 take both physics and chemistry, so:

B \cap C = 75

30 take both physics and calculus, so:

A \cap B = 30

Solution:

The problem states that 180 take calculus. So

a + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 180

a + 30 + 75 + 15 = 180

a = 180 - 120

a = 60

Twice as many students take chemistry as take physics:

It means that: C = 2B

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

B = b + 75 + 30 + 15

B = b + 120

-------------------------------

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

C = c + 75 + 75 + 15

C = c + 165

----------------------------------

Our interest is the number of student that take physics. We have to find B. For this we need to find b. We can write c as a function o b, and then replacing it in the equations that sums all the subsets.

C = 2B

c + 165 = 2(b+120)

c = 2b + 240 - 165

c = 2b + 75

The equation that sums all the subsets is:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) + D = 360

60 + b + 2b + 75 + 30 + 75 + 15 + 15 = 360

3b + 270 = 360

3b = 90

b = \frac{90}{3}

b = 30

30 students take only physics.

The number of student that take physics is:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

B = b + 75 + 30 + 15

B = 30 + 120

B = 150

150 students take physics.

6 0
2 years ago
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