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Answer:
Step-by-step explanation:
Hello!
You need to construct a 95% CI for the population mean of the length of engineering conferences.
The variable has a normal distribution.
The information given is:
n= 84
x[bar]= 3.94
δ= 1.28
The formula for the Confidence interval is:
x[bar]±
*(δ/n)
Lower bound(Lb): 3.698
Upper bound(Ub): 4.182
Error bound: (Ub - Lb)/2 = (4.182-3.698)/2 = 0.242
I hope it helps!
Answer:
0.159
Step-by-step explanation:
Given that:
Sample size (n) = 100
Population mean(pm) = 50
Standard deviation (s) = 8
Probability that Sample mean (m) will be greater Than 50.8
Using the relation :
(sample mean - population mean) / (standard deviation /sqrt(n))
P(m > 50.8)
Z = (50.8 - 50) / (8/ sqrt(100))
Z = 0.8 / (8/ 10)
Z = 0.8 / 0.8
Z = 1
P(Z > 1) = 0.15866 ( Z probability calculator)
Hence,
P(Z > 1) = 0.159 ( 3 decimal places)
Cincinnati
Ohio à<span>
Charlote North CA = a total of 336 miles
Cincinnati </span>à<span>
Chicago Illinois = a total of 247 miles
Perry drove from Charlote to Chicago by passing Cincinati. Find the distance she
drove.
=> Note that the distance from charlotte to Cincinnati is 365 then from
Cincinnati to Chicago is 247
=> 336 miles + 247 Miles
=> 583 miles
Penny drove for a total of 583 miles from Charlotte to Cincinnati to Chicago.
</span>