Vanna is saving for a trip. The hotel room will be $298.17 for 3 nights, and there will be additional fees. What is her daily co
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<h2><u>Answer with explanation</u>:</h2>
As per given , we have
sample size : n= 65
degree of freedom : df=n-1=64
sample mean :
sample standard deviation : s= 5.2
Since , the population standard deviation is not given , so we apply t-test.
Significance level for 90% confidence :
t-critical value for significance level 0.10 and df = 64 would be :
Formula for Confidence interval :
Then , 90% confidence intervals for the population mean number of weekly customer contacts for the sales personnel would be :
∴ 90% confidence intervals for the population mean number of weekly customer contacts for the sales personnel : (18.424, 20.576)
Significance level for 95% confidence :
t-critical value for significance level 0.05 and df = 64 would be :
Then , 95% confidence intervals for the population mean number of weekly customer contacts for the sales personnel would be :
∴ 95% confidence intervals for the population mean number of weekly customer contacts for the sales personnel : (18.212, 20.788)