X=his fortune
15/16X=7500
X=7500 x 16/15
X=8000
Round 1.05 mm to the nearest whole number the result is -1.1 then round 2.48 which the result will be equal to 3. The total variation in water level is -3.3
Since the Venus orbits round the sun, the sun is the center of the circular path of the revolution of the planet, Venus.
Thus, the distance of the planet, Venus fron the sun is given by the distance between the points (0, 0) and (41, 53).
Recall that the distance between two points

and

is given by

Thus, the distance between the points (0, 0) and (41, 53) is given by:

Given that each unit of the plane represents 1 million miles, therefore, the distance from the sun to the Venus is 67 million miles.
Years for one serious accident is 10 year
<u>Given:</u>
Probability of having a serious accident = 10% every year
P(serious accident) = 0.1
Number of years = n
<u>Computation:</u>
Years for one serious accident = 1 / Probability of having a serious accident
Years for one serious accident = 1 / P(serious accident)
Years for one serious accident = 1 / 0.1
Years for one serious accident = 10 year
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Let’s look at the permutations of the letters “ABC.” We can write the letters in any of the following ways:
ABC
ACB
BAC
BCA
CBA
CAB
Since there are 3 choices for the first spot, two for the next and 1 for the last we end up with (3)(2)(1) = 6 permutations. Using the symbolism of permutations we have:

. Note that the first 3 should also be small and low like the second one but I couldn’t get that to look right.
Now let’s see how this changes if the letters are AAB. Since the two As are identical, we end up with fewer permutations.
AAB
ABA
BAA
To make the point a bit better let’s think of one A are regular and one as bold
A.
ABA and AB
A look different now because we used bold for one of the As but if we don’t do this we see that these are actual the same. If they represented a word they would be the same exact word.
So in this case the formula would be

. We use 2! In the denominator because there are 2 repeating letters. If there were three we would use 3!
Hopefully, this is enough to let you see that the answer is A. The number of permutations is limited by the number of items that are identical.