system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y is 
and 
.
<u>Step-by-step explanation:</u>
Here we have , A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $4 more than the first customer for 1 large candle and 8 small candles. The price of each large candle is the same, and the price of each small candle is the same. We need to find Which system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y . Let's find out:
Let the price in dollars of each large candle, x, and each small candle, y .So
A customer at a store paid $64 for 3 large candles and 4 small candles
Equation is :
⇒ .....(1)
At the same store, a second customer paid $4 more than the first customer for 1 large candle and 8 small candles.
Equation is :
⇒ .......(2)
3(2)-(1) i.e.
⇒ 
⇒ 
⇒ 
So ,
⇒ 
⇒ 
Therefore , system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y is and .
Answer:
She chose Option 2 which is a linear option, because it offers a smaller lose
in value compared to option 1 which is an exponential option.
The final value for option 2=$32,800
Step-by-step explanation:
Option 1
New Zoomba for 60000 with a depreciation rat of 2%per month for 3 years
Exponential equation;
y=a(1-r)^t
where;
y=future value
a=initial value=60000
r=depreciation rate=2% per month
t=time interval=12×3=36 months
Replacing;
y=60000(1-2/100)^36
y=60000(0.98)^36=28,992.79
The value after 3 years=$28,992.79
Initial value-Final value=(60000-28992.79)=$31007.21
Percentage of initial value lost=((Final value-Initial Value)/(Initial Value))×100
(31007.21/60000)×100=51.68%
Option 2
New starfish for $40,000 with a depreciation of $200 per month for 3 years
Linear equation;
y=a-bt
where;
y=Future value
a=Initial value=$40,000
b=the depreciation amount per time interval=$200 per month for 3 years
t=time interval=(3×12)=36 months
Replacing;
y=40000-(200×36)
y=32,800
Final value=y=$32,800
Initial value-Final value=(40000-32800)=$7200
Percentage of initial value lost=((Final value-Initial Value)/(Initial Value))×100
(7200/40000)×100=18%
Option 1(51.68%)>Option 2(18%) therefor Option 1 loses value at a faster rate than Option 2
She chose Option 2 which is a linear option, because it offers a smaller lose
in value compared to option 1 which is an exponential option
when rounding numbers: if it's four or less, you round down. if it's five or more, you round up. 9 is bigger than 4, so the nearest whole number is 830.
Answer:
In a part-to-whole ratio, one ratio compares a part to a whole.
A = {1, 2, 5, 6, 8}
{1} U {2, 5, 6, 8}
{2} U {1, 5, 6, 8}
{5} U {1, 2, 6, 8}
{6} U {1, 2, 5, 8}
{8} U {1, 2, 5, 6}
{1, 2} U {5, 6, 8}
{1, 5} U {2, 6, 8}
{1, 6} U {2, 5, 8}
{1, 8} U {2, 5, 6}
{1, 2, 5} U {6, 8}
{1, 2, 6} U {5, 8}
{1, 2, 8} U {5, 6}
{1, 5, 6} U {2, 8}
{1, 5, 8} U {2, 6}
{1, 6, 8} U {2, 5}
The answer is 15 distinct pairs of disjoint non-empty subsets.
